我试图使一个购物清单,但每次我删除一个项目,它留下了一个很大的差距,看起来很尴尬,请有人能帮助,我仍然是非常新的这一切,我只学了一两个月,所以一个简单的答案将是非常感谢:
def subtract(user):
x = 0
while x == False:
answer = input("What would you like to subtract?")
if answer in user:
user = user.replace(answer,"")
y = 0
print("your list is:" + user)
add_or_subtract(user)
x == True
break
else:
print ("sorry, I do not recognise this, please try again.")
def add(user):
x = 0
while x == False:
answer = input(str("what would you like to add?".lower()))
if answer in user:
print ("sorry, this is already in the list")
else:
user = user + "\n" + answer
print ("Your list is: " + user)
answer = input("are you finished adding?".lower())
if answer in ("yes", "yea", "ye"):
answer1 = input("do you want to subtract or finish?")
if answer1 in ("subtract"):
subtract(user)
x == True
break
elif answer1 in ("finish"):
print (user)
x == True
break
else:
print("Sorry I do not recognise this")
def add_or_subtract(user):
x = 0
while x == False:
answer = input ("do you want to add or subtract or finish?".lower())
if answer in ("add","addition"):
add(user)
x == True
break
elif answer in ("subtract","takeaway"):
subtract (user)
x == True
break
elif answer in ("complete", "finish"):
print ("your final list is: " + user)
x == True
break
else:
print ("sorry i do not recognise this")
def initial(user):
x = 0
while x == False:
user = input("please type out your first item:".lower())
content = input(str("your first item is "+ user + " are you content with that?".lower()))
if content in "no":
user = ""
continue
elif content in "yes":
add_or_subtract(user)
x == True
break
shopping = ""
initial(shopping)
还有,有没有更好的方法来做到这一点,我觉得有,我可以使用一个列表来记录所有的项目,有没有一种方法,我可以存储现有的列表到一个数据库,然后在更新时重用它?
1条答案
按热度按时间7bsow1i61#
出现间隙的原因是您忘记了
\n
字符(换行符),因此在替换时,请在回答之前放置'\n'
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