实际上,我使用此代码来访问此Web服务FahrenheitToCelsius方法,我得到了正确的响应,但当我尝试访问我的Web服务时,我得到了
java.io.IOException:HTTP请求失败,HTTP状态:500
错误,它指向transport.call(SOAP_ACTION, envelope);
SoapObject request = new SoapObject(NAMESPACE, METHOD_NAME);
//Use this to add parameters
request.addProperty("username",usr);
request.addProperty("password",pass);
request.addProperty("backOfficePartnerId",id);
//Declare the version of the SOAP request
SoapSerializationEnvelope envelope = new SoapSerializationEnvelope(SoapEnvelope.VER10);
envelope.setOutputSoapObject(request);
envelope.dotNet = true;
try {
HttpTransportSE transport = new HttpTransportSE(URL);
Log.i("bodyout", "" + envelope.bodyOut.toString());
transport.call(SOAP_ACTION, envelope);
// Get the SoapResult from the envelope body.
SoapObject result = (SoapObject)envelope.bodyIn;
System.out.println("result IN F TO C::"+result);
}catch(Exception e){
e.printStackTrace();
}
我得到了正确的响应,直到这里。我调试并检查了值,发送了正确的正文,而作为响应,bodyin为空。
3条答案
按热度按时间oxcyiej71#
HTTP状态:500是一个内部服务器错误,它可能与您的.NET服务器端编码有关。
plicqrtu2#
将VER10更改为VER11。SoapSerializationEnvelope信封=新的SoapSerializationEnvelope(SoapEnvelope.VER11)对我有效
lf3rwulv3#
我搜索了很多,但没有找到任何具体的解决方案。我解决了我的问题,下载新的服务器包(相同版本),并取代了以前的服务器包用新的。(关于Apache tomcat 7)