我正在为我正在使用的数据库做一个过滤功能。我想知道如何才能访问请求的网址。
下面是模型的代码。

from django.db import models

class User(models.Model):
    username = models.CharField(max_length=20, null=True)
    account_type = models.CharField(max_length=30, null=True)
    first_name = models.CharField(max_length=30, null=True)
    last_name = models.CharField(max_length=30, null=True)
    email = models.EmailField(max_length=254, null=True)

class Interest(models.Model):
    interest = models.CharField(max_length=200, null=True)
    listing_account = models.ForeignKey(ListingAccount, related_name='interests', on_delete=models.CASCADE, null=True)

    def __str__(self):
        return f"{self.interest}"

下面是views.py中的过滤函数。我如何找到它的URL路径？

class AccountFilterViewSet(generics.ListAPIView):
    queryset = ListingAccount.objects.all()
    serializer_class = ListingAccountSerializer
    filter_backends = [filters.SearchFilter]
    search_fields = ['first_name']