在本周的tidytuesday
挑战中,由于某种原因,我无法对R中的列名进行分组,这是我之前使用tidyr
中的pivot_longer
函数所做的。因此,这是我的代码,我不明白为什么它会抛出一个错误,而不是给予我想要的。
library(tidyverse)
tuesdata <- tidytuesdayR::tt_load(2023, week = 7)
age_gaps <- tuesdata$age_gaps
df_long <- age_gaps %>%
pivot_longer(cols= actor_1_name:actor_2_name, names_to = "actornumber", values_to = "actorname") %>%
pivot_longer(cols= character_1_gender:character_2_gender, names_to = "gendernumber", values_to = "gender") %>%
pivot_longer(cols= actor_1_age:actor_2_age, names_to = "agenumber", values_to = "age") %>%
select(movie_name, release_year, director, age_difference, actorname, gender, age)
从代码中可以看出,初始数据有1155行,在快速处理数据后,我希望得到1155x2=2310行的数据,因为我想合并演员names
上的列及其相关信息,如age
和birthdate
。代码没有给予我预期的结果,我想知道为什么和如何才能解决这个问题。2谢谢你的关注。
示例数据(前6行)
age_gaps <- structure(list(movie_name = c("Harold and Maude", "Venus", "The Quiet American",
"The Big Lebowski", "Beginners", "Poison Ivy"), release_year = c(1971,
2006, 2002, 1998, 2010, 1992), director = c("Hal Ashby", "Roger Michell",
"Phillip Noyce", "Joel Coen", "Mike Mills", "Katt Shea"), age_difference = c(52,
50, 49, 45, 43, 42), couple_number = c(1, 1, 1, 1, 1, 1), actor_1_name = c("Ruth Gordon",
"Peter O'Toole", "Michael Caine", "David Huddleston", "Christopher Plummer",
"Tom Skerritt"), actor_2_name = c("Bud Cort", "Jodie Whittaker",
"Do Thi Hai Yen", "Tara Reid", "Goran Visnjic", "Drew Barrymore"
), character_1_gender = c("woman", "man", "man", "man", "man",
"man"), character_2_gender = c("man", "woman", "woman", "woman",
"man", "woman"), actor_1_birthdate = structure(c(-26725, -13666,
-13442, -14351, -14629, -13278), class = "Date"), actor_2_birthdate = structure(c(-7948,
4536, 4656, 2137, 982, 1878), class = "Date"), actor_1_age = c(75,
74, 69, 68, 81, 59), actor_2_age = c(23, 24, 20, 23, 38, 17)), row.names = c(NA,
-6L), class = c("tbl_df", "tbl", "data.frame"))
1条答案
按热度按时间rkttyhzu1#
您可以在
names_to
中设置".value"
,并提供names_sep
或names_pattern
之一来指定应如何拆分列名。