需要从数组"places"读取值-〉然后从数组"parents"读取值
来自我使用REST API接收的响应（$response）：
然后用$json = json_decode($response, true);解码
Array
(
[status_code] => 200
[data] => Array
(
[places] => Array
(
[0] => Array
(
[id] => 11878
[name] => Times Square
[name_suffix] => Manhattan, New York City, USA
[parents] => Array
(
[0] => Array
(
[id] => 32280039
[name] => Theater District
[level] => neighbourhood
)
[1] => Array
(
[id] => poi:28010161
[name] => Manhattan Community Board 5
[level] => region
)
[2] => Array
(
[id] => region:1981637
[name] => Manhattan Island
[level] => island
)
[3] => Array
(
[id] => poi:28043160
[name] => Manhattan
[level] => neighbourhood
)
)
[perex] => Times Square (nicknamed “The Crossroads of the World”) is the best known square in New York City and also its beating heart.
)
[1] => Array
(
[id] => 11874
[name] => Empire State Building
[name_suffix] => Manhattan, New York City, USA
[parents] => Array
(
[0] => Array
(
[id] => poi:32108808
[name] => Midtown South
[level] => neighbourhood
)
[1] => Array
(
[id] => poi:28010161
[name] => Manhattan Community Board 5
[level] => region
)
[2] => Array
(
[id] => region:1981637
[name] => Manhattan Island
[level] => island
)
[3] => Array
(
[id] => region:46071
[name] => Manhattan
[level] => neighbourhood
)
)
[perex] => An iconic Art Deco skyscraper and one of the best known buildings in New York. It got its name from the city’s nickname the "Empire State".
)
)
)
)我很难循环遍历对象，这些对象在请求时是未知的，并且对于每个单独的请求并不总是相同或可用的
foreach ($json->data as $places_list) {
foreach ($places_list->places as $placesItem) {
foreach($placesItem->(HELP HERE) as $place_detail) {
echo json_encode($place_detail) . "\n";
}
}
}您能否帮助实现一个通用函数，该函数允许（a）转到"位置"级别，然后（b）从"父级"检索值
谢谢你：）
2条答案
按热度按时间8e2ybdfx1#
你的代码与数据输出不匹配，因为它使用了对象表示法。但无论如何，这只是一个获得正确的数据层次结构的问题。
这段代码遍历
places数组的列表，并从那里回送名称，然后一个内部循环遍历parents元素并从那里输出名称其输出
f4t66c6m2#
我们正在开发一个带有递归函数的通用解决方案。json是数组和对象的混合体，这使得即使是ICT专业人士也很难导入它。稍后通过DM与我联系，它应该在2023年3月之前准备好。