我正在尝试做一个闪亮的应用程序,它包括一个侧边栏面板和一个绘图。在面板中,我有单选按钮来选择哪个ID应该被绘制。我也有多个变量,用户可以使用绘图图例关闭和打开。
我希望在应用程序第一次打开时绘图是空的。为此,我在绘图中使用了visible = "legendonly"
。但是,当在侧边栏面板中更改ID时,我希望保留用户已经激活的轨迹(通过在图例中单击它们);但是,由于绘图每次都重新生成,因此它再次使用visible = "legendonly"
选项,这将导致绘图重置。
当在侧边栏面板中选择了不同的选项时,有没有办法保留轨迹(只保留已经选择的轨迹)?
见以下可重现示例;请注意,我做了这个例子在本地运行。2你需要分别加载数据和包到你的R会话中。3数据可以在问题的底部找到。
library(shiny)
library(plotly)
library(lubridate)
### Read mdata into your R session
# UI
uix <- shinyUI(pageWithSidebar(
headerPanel("Data"),
sidebarPanel(
radioButtons('vars', 'ID',
c("1", "2")),
helpText('Select an ID.')
),
mainPanel(
h4("Plot"),
plotlyOutput("myPlot")
)
)
)
# SERVER
serverx <- function(input, output) {
#load("Data/mdata.RData") #comment out this part and load data locally
# a large table, reative to input$show_vars
output$uteTable = renderDataTable({
ute[, input$show_vars, drop = FALSE]
})
output$myPlot = renderPlotly(
{
p <- plot_ly() %>%
layout(title = "Title", xaxis = list(tickformat = "%b %Y", title = "Date"),
yaxis = list(title = "Y"))
## Add the IDs selected in input$vars
for (item in input$vars) {
mdata %>%
mutate(Date = make_date(Year, Month, 15)) %>%
filter(ID == item) -> foo
p <- add_lines(p, data = foo, x = ~Date, y = ~Value, color = ~Variable, visible = "legendonly",
evaluate = TRUE)
p <- p %>% layout(showlegend = TRUE,
legend = list(orientation = "v", # show entries horizontally
xanchor = "center", # use center of legend as anchor
x = 100, y=1))
}
print(p)
})
}
shinyApp(uix, serverx)
由reprex package(v0.3.0)于2020年6月12日创建
问题:当更改为ID == 2
时,是否可以保留Var1
跟踪?
***想法:***我认为如果我可以在应用部署后立即将visible = 'legendonly
更改为TRUE
,这将是可能的,因此它仅适用于情节的第一个示例。可能,我还需要将evaluate
更改为FALSE
。
数据:
mdata <- structure(list(Year = c(2015L, 2015L, 2015L, 2015L, 2015L, 2015L,
2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L,
2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L,
2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L,
2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L, 2015L,
2015L, 2015L, 2015L, 2015L, 2015L, 2015L), Month = c(1L, 1L,
1L, 1L, 2L, 2L, 2L, 2L, 3L, 3L, 3L, 3L, 4L, 4L, 4L, 4L, 5L, 5L,
5L, 5L, 6L, 6L, 6L, 6L, 7L, 7L, 7L, 7L, 8L, 8L, 8L, 8L, 9L, 9L,
9L, 9L, 10L, 10L, 10L, 10L, 11L, 11L, 11L, 11L, 12L, 12L, 12L,
12L), Variable = c("Var1", "Var1", "Var2", "Var2", "Var1", "Var1",
"Var2", "Var2", "Var1", "Var1", "Var2", "Var2", "Var1", "Var1",
"Var2", "Var2", "Var1", "Var1", "Var2", "Var2", "Var1", "Var1",
"Var2", "Var2", "Var1", "Var1", "Var2", "Var2", "Var1", "Var1",
"Var2", "Var2", "Var1", "Var1", "Var2", "Var2", "Var1", "Var1",
"Var2", "Var2", "Var1", "Var1", "Var2", "Var2", "Var1", "Var1",
"Var2", "Var2"), ID = c(1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1,
2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2,
1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2, 1, 2), Value = c(187.797761979167,
6.34656438541666, 202.288468333333, 9.2249309375, 130.620451458333,
4.61060465625, 169.033213020833, 7.5226940625, 290.015582677083,
10.8697671666667, 178.527960520833, 7.6340359375, 234.53493728125,
8.32400878125, 173.827054583333, 7.54521947916667, 164.359205635417,
5.55496292708333, 151.75458625, 6.361610625, 190.124467760417,
6.45046077083333, 191.377006770833, 8.04720916666667, 170.714612604167,
5.98860073958333, 210.827157916667, 9.46311385416667, 145.784868927083,
5.16647911458333, 159.9545675, 6.7466725, 147.442681895833, 5.43921594791667,
153.057018958333, 6.39029208333333, 165.6476956875, 5.63139815625,
197.179256875, 8.73210604166667, 148.1879651875, 5.58784840625,
176.859451354167, 7.65670020833333, 186.215496677083, 7.12404453125,
219.104379791667, 9.39468864583333)), class = c("grouped_df",
"tbl_df", "tbl", "data.frame"), row.names = c(NA, -48L), groups = structure(list(
Year = 2015L, .rows = list(1:48)), row.names = c(NA, -1L), class = c("tbl_df",
"tbl", "data.frame"), .drop = TRUE))
2条答案
按热度按时间f87krz0w1#
下面的代码使用
plotlyProxy
来替换现有绘图对象(和轨迹)的数据,从而避免了重新渲染绘图。这种方法比重新渲染更快。有关详细信息,请参见plotly book中的"17.3.1部分绘图更新"一章,绘图的函数参考和this answer。
数据:
下面是一个替代服务器函数,它使用单个
plotlyProxyInvoke
调用更新跟踪数据(避免for循环):jm81lzqq2#
我所能想到的是添加一个复选框来选择要绘制的变量,而不是在图例中关闭和打开它们。使用这种方法,而不是使用
visible = legendonly
,我让复选框没有选中默认值。此外,当用户更改ID时,变量保持不变,因此为下一个ID绘制。见下文;