我为我的应用程序配置了动态链接，但它在Android上运行得很好，但它只引导我到应用程序商店，而不是实际的应用程序。

• • Flutter 医生-v**

[!] Flutter (Channel stable, 3.7.3, on macOS 13.1 22C65 darwin-arm64, locale en-KR)
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! Doctor found issues in 3 categories.

• • 安卓清单. xml**

....
            <intent-filter>
                <action android:name="android.intent.action.VIEW"/>
                <category android:name="android.intent.category.DEFAULT"/>
                <category android:name="android.intent.category.BROWSABLE"/>
                <data
                android:host="incle.page.link" 
                android:scheme="https" />
                <data
                android:host="incle.page.link" 
                android:scheme="http" />
            </intent-filter>
....

• • iOS配置**
• • 信息列表**

...
    <key>FirebaseDynamicLinksCustomDomains</key>
    <array>
        <string>https://incle.page.link/share</string>
    </array>
...
<array>
        <dict>
            <key>CFBundleTypeRole</key>
            <string>Editor</string>
            <key>CFBundleURLName</key>
            <string>Bundle ID</string>
            <key>CFBundleURLSchemes</key>
            <array>
                <string>com.incle.incleClientApp</string>
            </array>
        </dict>
    </array>
...

• • 跑步者权利**

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE plist PUBLIC "-//Apple//DTD PLIST 1.0//EN" "http://www.apple.com/DTDs/PropertyList-1.0.dtd">
<plist version="1.0">
<dict>
    <key>aps-environment</key>
    <string>development</string>
    <key>com.apple.developer.associated-domains</key>
    <array>
        <string>applink:incle.page.link</string>
    </array>
</dict>
</plist>

• • 我创建动态链接的方式**

Future<void> onClickShare(String storeID) async {
    final dynamicLinkParams = DynamicLinkParameters(
        link: Uri.parse(
            "https://incle.page.link/share?route=${StoreDetailScreen.routeName}&argument=$storeID"),
        uriPrefix: "https://incle.page.link",
        androidParameters:
            const AndroidParameters(packageName: "com.incle.incle_client_app"),
        iosParameters:
            const IOSParameters(bundleId: "com.incle.incleClientApp"),
        socialMetaTagParameters: SocialMetaTagParameters(
            description: storeInfoState.value!.data!.storeDescription,
            imageUrl: Uri.parse(storeInfoState.value!.data!.storeImage.isEmpty
                ? ''
                : storeInfoState.value!.data!.storeImage.first),
            title: storeInfoState.value!.data!.storeName));
    final dynamicLink = await FirebaseDynamicLinks.instance.buildShortLink(
        dynamicLinkParams,
        shortLinkType: ShortDynamicLinkType.short);

    Share.share(dynamicLink.shortUrl.toString());
  }

我相信我详细阐述了所有需要的配置，使Firebase动态链接在Flutter上工作。它在Android上的工作就像魔术一样。
但在iOS上，当我点击预览页面中的"打开链接"按钮时，它只会将我重定向到应用商店。我不知道如果我用带调试器的应用测试它是否有问题，但至少它不适用于Testflight安装的应用。
请帮助我，拯救我的一天大师们!非常感谢。