如上所述,我尝试使用www.example.com_sql查询mysql数据库,并得到一个双引号/单引号错误。pd.read_sql to query our mysql database, and getting an error for double/single quotes.
当我从LIKE子句(第84 - 87行)中删除%操作符时,查询会运行,但这些操作符是必需的。我知道我需要格式化字符串,但我不知道在这么大的查询中如何格式化。
下面是查询:
SELECT
s.offer_id,
s.cap_id,
vi.make,
vi.model,
vi.derivative,
i.vehicle_orders,
s.lowest_offer,
CASE
WHEN f.previous_avg = f.previous_low THEN "n/a"
ELSE FORMAT(f.previous_avg, 2)
END as previous_avg,
f.previous_low,
CASE
WHEN ( ( (s.lowest_offer - f.previous_avg) / f.previous_avg) * 100) = ( ( (s.lowest_offer - f.previous_low) / f.previous_low) * 100) THEN "n/a"
ELSE CONCAT(FORMAT( ( ( (s.lowest_offer - f.previous_avg) / f.previous_avg) * 100), 2), "%")
END as diff_avg,
CONCAT(FORMAT( ( ( (s.lowest_offer - f.previous_low) / f.previous_low) * 100), 2), "%") as diff_low,
s.broker,
CASE
WHEN s.in_stock = '1' THEN "In Stock"
ELSE "Factory Order"
END as in_stock,
CASE
WHEN s.special IS NOT NULL THEN "Already in Specials"
ELSE "n/a"
END as special
FROM
( SELECT o.id as offer_id,
o.cap_id as cap_id,
MIN(o.monthly_payment) as lowest_offer,
b.name as broker,
o.stock as in_stock,
so.id as special
FROM
offers o
INNER JOIN brands b ON ( o.brand_id = b.id )
LEFT JOIN special_offers so ON ( so.cap_id = o.cap_id )
WHERE
( o.date_modified >= DATE_ADD(NOW(), INTERVAL -1 DAY) OR o.date_created >= DATE_ADD(NOW(), INTERVAL -1 DAY) )
AND o.deposit_value = 9
AND o.term = 48
AND o.annual_mileage = 8000
AND o.finance_type = 'P'
AND o.monthly_payment > 100
GROUP BY
o.cap_id
ORDER BY
special DESC) s
INNER JOIN
( SELECT o.cap_id as cap_id,
AVG(o.monthly_payment) as previous_avg,
MIN(o.monthly_payment) as previous_low
FROM
offers o
WHERE
o.date_modified < DATE_ADD(NOW(), INTERVAL -1 DAY)
AND o.date_modified >= DATE_ADD(NOW(), INTERVAL -1 WEEK)
AND o.deposit_value = 9
AND o.term = 48
AND o.annual_mileage = 8000
AND o.finance_type = 'P'
AND o.monthly_payment > 100
GROUP BY
o.cap_id ) f ON ( s.cap_id = f.cap_id )
LEFT JOIN
( SELECT a.cap_id as cap_id,
v.manufacturer as make,
v.model as model,
v.derivative as derivative,
COUNT(*) as vehicle_orders
FROM
( SELECT o.id,
o.name as name,
o.email as email,
o.date_created as date,
SUBSTRING_INDEX(SUBSTRING(offer_serialized, LOCATE("capId", offer_serialized) +12, 10), '"', 1) as cap_id
FROM moneyshake.orders o
WHERE o.name NOT LIKE 'test%'
AND o.email NOT LIKE 'jawor%'
AND o.email NOT LIKE 'test%'
AND o.email NOT LIKE '%moneyshake%'
AND o.phone IS NOT NULL
AND o.date_created > DATE_ADD(NOW(), INTERVAL -1 MONTH)
) a JOIN moneyshake.vehicles_view v ON a.cap_id = v.id
GROUP BY
v.manufacturer,
v.model,
v.derivative,
a.cap_id) i ON ( f.cap_id = i.cap_id )
INNER JOIN
( SELECT v.id as id,
v.manufacturer as make,
v.model as model,
v.derivative as derivative
FROM moneyshake.vehicles_view v
GROUP BY v.id ) vi ON s.cap_id = vi.id
WHERE
( ( s.lowest_offer - f.previous_low ) / f.previous_low) * 100 <= -15
GROUP BY
s.cap_id
谢谢!
2条答案
按热度按时间e4yzc0pl1#
如果发生该错误,DBAPI层(例如mysqlclient)会本机使用"format"参数样式,并且百分号(
%
)被误认为是格式字符,而不是LIKE
通配符。修复方法是将SQL语句 Package 在SQLAlchemy
text()
对象中。例如,这将失败:而是简单地将
read_sql_query()
调用更改为会起作用。
pu82cl6c2#
我在Python 3.7中遇到过同样的问题,在我的例子中,解决方案只是在所有like子句中用%%替换%。