要从Json对象中删除重复项，可以使用以下代码：

from collections import OrderedDict

data = {
    "query1": [
        {"name": "John", "id": 1234},
        {"name": "Rose", "id": 3214},
        {"name": "John", "id": 1234},
    ]
}

unique_data = {}
for key, array in data.items():
    unique_objects = OrderedDict()
    for obj in array:
        unique_objects[(obj["name"], obj["id"])] = obj
    unique_data[key] = list(unique_objects.values())

print(unique_data)

结果：

{'query1': [{'name': 'John', 'id': 1234}, {'name': 'Rose', 'id': 3214}]}

这样做是可能的，找到了答案here：

data = {
    "query1": [
        {"name": "John", "id": 1234},
        {"name": "Rose", "id": 3214},
        {"name": "John", "id": 1234},
    ]
}

query1 = data.get('query1')

[dict(t) for t in {tuple(d.items()) for d in query1}]

在JSONiq中，您确实可以使用group by和数组取消装箱来删除重复项，如下所示：

let $data := {
  "query1" : [
    { "name" : "John", "id" : 1234 },
    { "name" : "Rose", "id" : 3214 },
    { "name" : "John", "id" : 1234 }
  ]
}
return {
 "query1" : [
    for $obj in $data.query1[]
    group by $n := $obj.name, $i := $obj.id
    return $obj[1]
  ]
}

还有一种通用的方法，即使是未知字段和嵌套较多的值也可以使用：

let $data := {
  "query1" : [
    { "name" : "John", "id" : 1234 },
    { "name" : "Rose", "id" : 3214 },
    { "name" : "John", "id" : 1234 }
  ]
}
return {
  "query1" : [
    for $obj at $i in $data.query1[]
    where
      every $other in $data.query1[][position() lt $i]
      satisfies not deep-equal($obj, $other)
    return $obj
  ]
}