• • 此问题在此处已有答案**：

Stop an input field in a form from being submitted（14个答案）
昨天关门了。
因此，我使用HTML和PHP构建一个表单，它将接受两个参数，然后调用API并构建一个表单。
下面是HTML：

<div class="login-page">
  <div class="form">
    <span>Enter the Customer Load Number and Pickup Zip Code, then click "Submit" to track your shipment.</span>
      <form action="#" method="GET" style="margin-top: 20px">
      <!-- <label for="reference">Customer Load Number:</label> -->
      <input type="text" id="reference" name="reference" placeholder="Customer Load Number" value="<?php echo !empty($_GET['reference']) ?htmlspecialchars($_GET['reference']) :''; ?>" required="" />
      <!-- <label for="zipcode">Pickup Zipcode:</label> -->
      <input type="text" id="zipcode" name="zipcode" placeholder="Pickup zipcode" value="<?php echo !empty($_GET['zipcode']) ?htmlspecialchars($_GET['zipcode']) :''; ?>" required="" />
      <input type="submit" name="submit" value="Submit" style="margin-top: 20px; justify-content: center" />
    </form>
  </div>
</div>

然后，一旦输入客户装载编号和邮政编码，用户提交表单，它将装载并执行一些PHP w/HTML输出：

<?php if (isset($_GET['submit'])) {
    $reference = sanitize_text_field($_GET['reference']);
    $zipcode = intval($_GET['zipcode']);

    $curl = curl_init();
    $link = "https://example.net/customer-portal/tracking?reference=$reference&postalCode=$zipcode";
    curl_setopt_array($curl, [
    CURLOPT_URL => "$link",
    CURLOPT_RETURNTRANSFER => true,
    CURLOPT_ENCODING => "",
    CURLOPT_MAXREDIRS => 10,
    CURLOPT_SSL_VERIFYPEER => false,
    CURLOPT_TIMEOUT => 30,
    CURLOPT_HTTP_VERSION => CURL_HTTP_VERSION_1_1,
    CURLOPT_CUSTOMREQUEST => "GET",
    CURLOPT_POSTFIELDS => "------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: form-data; name=\"Reference\"\r\n\r\n2889615\r\n------WebKitFormBoundary7MA4YWxkTrZu0gW\r\nContent-Disposition: form-data; name=\"postalCode\"\r\n\r\n35956\r\n------WebKitFormBoundary7MA4YWxkTrZu0gW--",
    CURLOPT_HTTPHEADER => [
        "AccountId: si",
        "Authorization: Basic d2Vic-----",
        "Postman-Token: 0fdfa047-----",
        "cache-control: no-cache"
    ],
    ]);
    $response = curl_exec($curl);
    $err = curl_error($curl);
    curl_close($curl);
    $response = json_decode($response);

    if ($response->Data === null) {
        $message =
            '<p style="text-align: center; margin-top: -50px; margin-bottom: 60px;">The provided Customer Load Number and <br/>Pickup Zipcode combination could not be validated.</p>';
        echo $message;
    } else {
        $data = $response;
    }
}
?>

• • 问题**：

当用户提交表单时，它将构建以下参数并提交表单：www.example.comhttps://example.com.test/customers/?reference=P337574&zipcode=50219&submit=Submit#
我怎么能有提交表单的选项，但排除submit参数，所以我想使用以下参数提交表单：https://example.com.test/customers/?reference=P337574&zipcode=50219
当我当前删除提交时，表单不会自动提交。
我试过输入submit参数，也试过删除它。