java 休眠:“order子句”中的列“column_name”未知

w46czmvw  于 2023-03-16  发布在  Java
关注(0)|答案(1)|浏览(131)

在过去的两周里,我一直在学习Hibernate,但是我现在遇到了一个我无法解决的问题,我也不幸运地在网上找到了解决方案。

我的问题:我希望一条消息有多个响应。我有@OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)@JoinColumn(name = "message_id")@OrderBy("response_date DESC")作为响应列表。response_date属于响应表。每当我试图查找消息时,我总是看到以下错误:

[错误] [2023年3月13日上午3:14:28:025|GMT-05:00] [主要] [组织.休眠.引擎.jdbc.spi.SqlExceptionHelper.日志异常(SqlExceptionHelper.java:142)] -“订单子句”中存在未知列“消息su0_.response_date”
线程“main”中出现异常。组织休眠。异常。SQLGrammarException:无法提取结果集...
我从数据库中删除了表,然后注解掉了@OrderBy("response_date DESC")注解,添加了一条消息,然后尝试再次查找该消息,但仍然显示相同的错误。
我到底做错了什么?

消息.java

@Entity
@Table(name = "Message")
public class Message implements Serializable {
    @Transient
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.TABLE)
    @Column(name = "message_id", nullable = false)
    private int messageID;

    @Column(name = "type", nullable = false, length = 50)
    private String messageType;

    @Column(name = "category", nullable = false, length = 100)
    private String category;

    @Column(name = "details", nullable = false, length = 2000)
    private String details;

    @Column(name = "date_created", nullable = false)
    @Temporal(TemporalType.TIMESTAMP)
    private Date dateCreated;

    @Column(name = "resolved")
    private boolean resolved;

    @OneToOne(cascade = CascadeType.MERGE)
    @JoinColumn(name = "student_id")
    private Student student;

    @OneToOne(cascade = CascadeType.MERGE)
    @JoinColumn(name = "staff_id")
    private Staff staff;

    @OneToMany(cascade = CascadeType.ALL, fetch = FetchType.LAZY)
    @JoinColumn(name = "message_id")
    @OrderBy("response_date DESC") // commented out here and still seeing the same error about unknown column
    private List<Response> responses;

    // Constructors
    // Getters & Setters
}

响应.java

@Entity
@Table(name = "Response")
public class Response implements Serializable {
    @Transient
    private static final long serialVersionUID = 1L;

    @Id
    @GeneratedValue(strategy = GenerationType.TABLE)
    @Column(name = "response_id", nullable = false)
    private int responseID;

    @Column(name = "content", nullable = false, length = 2000)
    private String content;

    @Column(name = "response_date", nullable = false)
    @Temporal(TemporalType.TIMESTAMP)
    private Date responseDate;

    @OneToOne(cascade = CascadeType.MERGE)
    @JoinColumn(name = "message_id")
    private Message message;

    // Constructors
    // Getters & Setters
}

我用来做参考的是我的另一门课...

员工.java

@Entity
@Table(name = "Staff")
@PrimaryKeyJoinColumn(name = "user_id")
public class Staff extends User implements Serializable {
    @Transient
    private static final long serialVersionUID = 1L;

    @Column(name = "role", length = 255)
    private String role;

    @OneToMany(fetch = FetchType.LAZY)
    @JoinColumn(name = "staff_id")
    @OrderBy("date_created DESC") // order by date_created which is from the message table and it worked
    private List<Message> assignedMessages;

    // Constructors 
    // Getters & Setters
}

在向消息类添加响应列表之前,一切都很正常,当我查找一个工作人员时,我会返回由该工作人员发送的消息列表。
我哪里做错了?任何帮助或解释都将不胜感激。

xxls0lw8

xxls0lw81#

@OrderBy注解中,应使用实体字段而不是数据库列名:

@OrderBy("responseDate DESC")

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