DECLARE @Table TABLE (nums DECIMAL(5,1))
INSERT INTO @Table
VALUES  (35),(53),(64)

SELECT  nums,
        (Convert(int,(nums/10)) + 1) * 10 AS Roundoff
FROM @Table

Result

nums Roundoff
35.0    40
53.0    60
64.0    70

You can't use ROUND directly for that, as there's no inbuilt mechanism to do so.

But you can easily just do it another way:

SELECT ( ( ( x - 1 ) / 10 ) + 1 ) * 10

This way you:

Subtract one divide by 10, discarding any rest beyond full 10s, meaning You'll turn 63 into 6 or 70 into 6 (this is important because you don't want to round 70 to 80, I presume. If you do, just don't subtract 1 before dividing). Then add one (this is the rounding up part) and multiply back up by 10.

If you need to use this a lot you can define a custom function to do it for you.

Another way:

DECLARE @t TABLE (X INT)
INSERT INTO @t (X) VALUES(30),(31),(33),(39),(43),(53),(63),(73)

Select X, round(X + 9, -1, 1) Rounded
FROM @t

+----+---------+
| X  | Rounded |
+----+---------+
| 30 |      30 |
| 31 |      40 |
| 33 |      40 |
| 39 |      40 |
| 43 |      50 |
| 53 |      60 |
| 63 |      70 |
| 73 |      80 |
+----+---------+

Best way is to use ceil, you can do:

SELECT ceil(amount / 10) * 10

For example, 50 would stay 50. 51 through 60 would be 60. 61 would be 70 and so on.

DECLARE @t TABLE (X INT)
INSERT INTO @t (X) VALUES(33),(43),(53),(63),(73)

Select floor((X + 9) / 10) * 10
FROM @t

Returns

40
50
60
70
80