我有两个列表，大致如下所示：

val localList = listOf(
 HumanValue(id = "abc", gamesPlayed=7, gamesWon=4, removed=false),
 HumanValue(id = "abcd", gamesPlayed=1, gamesWon=0, removed=false),
 HumanValue(id = "abcde", gamesPlayed=6, gamesWon=3, removed=false),
 HumanValue(id = "abcdef", gamesPlayed=12, gamesWon=12, removed=false)
)

val remoteList = listOf(
 HumanValue(id = "abc", gamesPlayed=12, gamesWon=7, removed=false),
 HumanValue(id = "abcd", gamesPlayed=1, gamesWon=0, removed=false),
 HumanValue(id = "abcde", gamesPlayed=6, gamesWon=3, removed=true),
 HumanValue(id = "abcdef", gamesPlayed=12, gamesWon=12, removed=false),
 HumanValue(id = "abcdefg", gamesPlayed=0, gamesWon=0, removed=false)
)

我想要的是最新的列表成为规范列表，所以游戏数量最多的项目将是最新的，因此是规范的。每个项目的默认状态也是它还没有被删除，所以如果它已经被删除，这是故意的，因此是规范的。
我可以用forEach遍历更长列表中的每一个，然后将游戏播放次数最多的列表添加到第三个列表，然后将这些列表中的每一个都设置到第三个列表，但这感觉不是最佳实践/习惯用法/高效等。
有没有其他的方法可以做到这一点，例如使用Kotlin方法，如mapping或flatmapping或其他方法？
编辑：这是我想到的最好的方法，但在我看来却很糟糕：

suspend fun compareDBs() {
    if ((localDeck.value?.size == remoteDeck.value?.size) && (localDeck.value?.toSet() == remoteDeck.value?.toSet())) { return }
    else {
      val diff1: MutableList<HumanValue> = mutableListOf(localDeck.value?.minus(arrayOf(remoteDeck).toSet())) as MutableList<HumanValue>
      val diff2 = remoteDeck.value?.minus(arrayOf(localDeck).toSet()) as MutableList<HumanValue>

      val listOfDifferences = mutableListOf<HumanValue>()
      listOfDifferences.addAll(diff1)
      listOfDifferences.addAll(diff2)

      listOfDifferences.forEach {diffValue ->
        val localVersion = localDeck.value?.filter { it.id == diffValue.id }
        val remoteVersion = remoteDeck.value?.filter { it.id == diffValue.id }
        
        if (!localVersion.isNullOrEmpty() && !remoteVersion.isNullOrEmpty()) {
          if (localVersion[0].gamesPlayed > remoteVersion[0].gamesPlayed) { localIsCanonical() }
          else { remoteIsCanonical() }
        }
        else {
          if (localVersion.isNullOrEmpty()) { remoteIsCanonical() }
          else if (remoteVersion.isNullOrEmpty()) { localIsCanonical() }
        }
      }
    }
  }