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我使用谷歌API来拉取某组项目的图像地址。每当我在终端中运行代码时，“节点C：\Users\rest_of_file_name\get_image_url.mjs”
它返回“fetch不是函数”。
我的节点版本：v18.15.0。
下面是我的代码：

/**
 * @param {string} searchTerm - Search term for Google Image search.
 * @param {function(string,number,number)} callback - Called when an image has
 *   been found. The callback gets the URL, width and height of the image.
 * @param {function(string)} errorCallback - Called when the image is not found.
 *   The callback gets a string that describes the failure reason.
 */

import fetch from "node-fetch";

const key = 'flkfjslksj';
const cx = 'sfkjlkfjlk';

function getImageUrl(searchTerm, callback, errorCallback) {
  var searchUrl = 'https://www.googleapis.com/customsearch/v1' +
    '?key=' + key + '&cx=' + cx + '&searchType=image&q=' + encodeURIComponent(searchTerm);

  import('node-fetch')
    .then(fetch => {
      return fetch(searchUrl);
    })
    .then(res => res.json())
    .then(json => {
      var response = json;
      if (!response || !response.items || response.items.length === 0) {
        errorCallback('No response from Google Image search!');
        return;
      }
      var firstResult = response.items[0];
      var imageUrl = firstResult.link;
      var width = parseInt(firstResult.image.width);
      var height = parseInt(firstResult.image.height);
      console.assert(
        typeof imageUrl == 'string' && !isNaN(width) && !isNaN(height),
        'Unexpected respose from the Google Image Search API!');
      callback(imageUrl, width, height);
    })
    .catch(error => {
      errorCallback(error.message);
    });
}

const items = ['Fine Line', 'Lemon Boy', 'The Life of Pablo'];
for (const item of items) {
  getImageUrl(item, function (imageUrl, width, height) {
    console.log(imageUrl, width, height);
  }, function (errorMessage) {
    console.error(errorMessage);
  });
}

我认为这与fetch函数有关，只是不知道如何修复它。
它实际上成功地工作了一次。但是，当我再次运行它而不做任何更改时，我得到了fetch不是一个函数的错误。