我使用GString示例，因为我的计算机上没有工作Gradle：

pipeline{
    agent{label 'master'}
    stages{
        stage('1'){
            steps {
    script{
        def targetEnvironment="value1"
        def s1 = true
        def s2 = true
        def s3 = true
        def s4 = true
      String test1 = """
          -DtargetEnvironment=${targetEnvironment}
          -Dsimulations=${(getSimulations("$s1", "$s2", "$s3", "$s4"))}
      """
      echo test1
    }
    
  }
}
}
}

def getSimulations(s1, s2, s3, s4) {
  List<String> simulations = [
      s1 ? "Simulation1" : "",
      s2 ? "Simulation2" : "",
      s3 ? "Simulation3" : "",
      s4 ? "Simulation4" : ""
  ]
  
  return simulations.join(",")
}

你需要使用圆括号来调用函数，并在双引号内传递参数。你还需要在getSimulations函数中使用List<String>类型。
然而，为了更清晰，我将从该位置提取函数并仅传递结果变量：

def targetEnvironment="value1"
        def s1 = true
        def s2 = true
        def s3 = true
        def s4 = true
        def simParams = getSimulations(s1, s2, s3, s4)
      String test1 = """
          -DtargetEnvironment=${targetEnvironment}
          -Dsimulations=${simParams}
      """
      echo test1