假设lookup的键是从最短到最长排序的（也就是说，list可能更适合作为容器）：

def find(my_strings, lookup):
  for string in my_strings: # For each string
    matched = None
    
    for word in lookup:     # Check all words
      if word in string:    # If a match is found
        matched = word      # Assign to matched, even if it already has a non-None value
    
    print(f'{string}: {matched}')

试试看：

lookup = {
    'text_text': 1,
    'text_text_num': 1
}

my_strings = [
    'text_text_part1',
    'text_text_part2',
    'text_text_another_part3',
    'text_text_num_something_part3'
]

find(my_strings, lookup)
# text_text_part1: text_text
# text_text_part2: text_text
# text_text_another_part3: text_text
# text_text_num_something_part3: text_text_num