这与@rckoenes的答案没有根本的不同，但它确实提供了一种更正统的方式来处理视图上的事件，而不是使用不可见的按钮。
我宁愿在我的头视图中添加UITapGestureRecognizer，而不是添加不可见的按钮并调整它们的大小：

UITapGestureRecognizer *singleTapRecogniser = [[[UITapGestureRecognizer alloc] initWithTarget:self action:@selector(handleGesture:)] autorelease];
[singleTapRecogniser setDelegate:self];
singleTapRecogniser.numberOfTouchesRequired = 1;
singleTapRecogniser.numberOfTapsRequired = 1;   
[yourHeaderView addGestureRecognizer:singleTapRecogniser];

然后：

- (void) handleGesture:(UIGestureRecognizer *)gestureRecognizer;

你可以使用gesture.view查看哪个被触摸了，然后做任何你需要做的事情来找出它是哪个头（标签，数据数组查找…）

没有办法用UITableViewDelegate来做。
你可以做的是添加一个按钮，大小与section header视图相同，并将其添加到视图中。将按钮的标签设置为section index。然后添加UIViewController作为UIControlEventTouchUpInside的目标。
然后通过查看按钮的标签，您可以看到单击了哪个部分。

以下是我在Swift 2中的工作：

override func tableView(tableView: UITableView, viewForHeaderInSection section: Int) -> UIView? {
    let footerView = UITableViewHeaderFooterView()
    footerView.textLabel?.text = "Header Text"
    let tapRecognizer = UITapGestureRecognizer(target: self, action: #selector(handleTap))
    tapRecognizer.delegate = self
    tapRecognizer.numberOfTapsRequired = 1
    tapRecognizer.numberOfTouchesRequired = 1
    footerView.addGestureRecognizer(tapRecognizer)
    return footerView
}

@objc func handleTap(gestureRecognizer: UIGestureRecognizer) {
    print("Tapped")
}

这对评估部分和行起了作用。我希望它能帮助其他所有正在努力使这项工作正常进行的人...

override func viewDidLoad() {
    let tapGesture = UITapGestureRecognizer(target: self, action: #selector(sectionTapped(sender:)))
    tableView?.addGestureRecognizer(tapGesture)
    tapGesture.delegate = self as? UIGestureRecognizerDelegate
}

@objc func sectionTapped(sender: UITapGestureRecognizer) {
    if sender.state == UIGestureRecognizerState.ended {
        guard let tableView = self.tableView else {
            return
        }
        if let view = sender.view {
            let tapLocation = sender.location(in: tableView)
            if let tapIndexPath = tableView.indexPathForRow(at: tapLocation) {              
                if (tableView?.cellForRow(at: tapIndexPath) as? UITableViewCell) != nil {
                    // do something with the row
                    print("tapped on row at index: \(tapIndexPath.row)")
                }
            }  else {
                for i in 0..<tableView.numberOfSections {
                    let sectionHeaderArea = tableView.rectForHeader(inSection: i)
                    if sectionHeaderArea.contains(tapLocation) {
                        // do something with the section
                        print("tapped on section at index: \(i)")
                    }
                }
            }
        }
    }
}

这里是Taku的回答的一个更新版本。

override func viewDidLoad() {
        super.viewDidLoad()
        let tapGesture = UITapGestureRecognizer(target: self, action: #selector(sectionTapped(sender:)))
        tableView.addGestureRecognizer(tapGesture)
        tapGesture.delegate = self
    }

@objc func sectionTapped(sender: UITapGestureRecognizer) {
        guard sender.state == .ended else { return }
        
        let tapLocation = sender.location(in: tableView)
        if let tapIndexPath = tableView.indexPathForRow(at: tapLocation),
           let cell = tableView.cellForRow(at: tapIndexPath) {
            // TODO: Do something with row
            print("tapped on row at index: \(tapIndexPath.row)")
        } else {
            for section in 0..< tableView.numberOfSections {
                let headerRect = tableView.rectForHeader(inSection: section)
                if headerRect.contains(tapLocation) {
                    // TODO: Do something with the section
                    print("Tapped on section at index: \(section)")
                }
            }
        }
    }