javascript 如何使用find方法从这个对象数组中删除重复的元素？

11dmarpk 于 2023-04-04 发布在 Java

关注(0)|答案(2)|浏览(145)

我想将arr2的元素推入arr1，但它不应该复制这些元素

let arr = [{obj: "ABC"},{obj: "XYZ"},{obj: "LMN"}]
const arr2 = [{obj: "ABC"},{obj: "MNO"}]
 
arr2.forEach(j => {
           arr.find((e =>{
              if(j.obj !== e.obj){
                arr.push({ obj: `${j.obj}|` });
              }
           }))

JavaScript

来源：https://stackoverflow.com/questions/75916044/how-can-i-remove-the-duplicate-elements-from-this-array-of-objects-using-find-me

2条答案

按热度按时间

c3frrgcw1#

arr2.forEach(j => {
    if (!arr.some(e => e.obj === j.obj)) {
        arr.push({ obj: `${j.obj}|` });
    }
});

赞(0）回复(0）举报 2023-04-04

gzszwxb42#

const arr = [{id: 1, name: 'one'}, {id: 2, name: 'two'}, {id: 1, name: 'one'}]
const ids = arr.map(o => o.id)
const filtered = arr.filter(({id}, index) => !ids.includes(id, index + 1))
console.log(filtered)
============
otherwise here is similiar you can try
const persons= [
      { id: 1, name: 'John',phone:'23' },
      { id: 2, name: 'Jane',phone:'23'},
      { id: 1, name: 'Johnny',phone:'56' },
      { id: 4, name: 'Alice',phone:'67' },
    ];
const unique = [...new Map(persons.map((m) => [m.id, m])).values()];

赞(0）回复(0）举报 2023-04-04

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javascript 如何使用find方法从这个对象数组中删除重复的元素？

2条答案

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