你可以添加下面的方法，它会像一个魅力一样工作（当然，如果你让这些DTO正确的Jacson pojo（即默认构造函数+ setters/getter））

@JsonProperty("phoneList")
private void mapPhones(Map<String, List<Phone>> phoneList) {
  this.phoneList = phoneList.get("phone");
}

是的，你可以直接创建它。看看下面的代码：

1. Response类

class Response {

    String name;
    List<Phone> phoneList = new ArrayList<>();

    public Response() {
    }

    public String getName() {
        return name;
    }

    public void setName(String name) {
        this.name = name;
    }

    public List<Phone> getPhoneList() {
        return phoneList;
    }

    public void setPhoneList(List<Phone> phoneList) {
        this.phoneList = phoneList;
    }

    @Override
    public String toString() {
        return "Response{" + "name=" + name + ", phoneList=" + phoneList + '}';
    }

    class Phone {

        String number;
        Integer code;

        public String getNumber() {
            return number;
        }

        public void setNumber(String number) {
            this.number = number;
        }

        public Phone() {
        }

        public Integer getCode() {
            return code;
        }

        public void setCode(Integer code) {
            this.code = code;
        }

        @Override
        public String toString() {
            return "Phone{" + "number=" + number + ", code=" + code + '}';
        }
    }
}

1. Main类

public static void main(String[] args) throws JsonProcessingException {
    Response response = new Response();

    response.setName("test");

    Response.Phone phone = response.new Phone();
    phone.setNumber("32323232");
    phone.setCode(555);
    response.phoneList.add(phone);

    phone = response.new Phone();
    phone.setNumber("4343423432");
    phone.setCode(555);
    response.phoneList.add(phone);

    System.out.println(response.toString());

    ObjectMapper mapper = new ObjectMapper();
    mapper.enable(SerializationFeature.INDENT_OUTPUT);
    System.out.println(mapper.writeValueAsString(response));
}