示例：

mydf <- data.frame(x = 1:10, y = rnorm(10))
mydf[2,2] <- NA
mydf[5,1] <- NA

看起来像：

mydf
    x          y
1   1 -1.0198834
2   2         NA
3   3  0.6080986
4   4 -0.4124830
5  NA  0.1723944
6   6 -2.3869210
7   7 -0.9843615
8   8 -1.3187416
9   9  0.1794670
10 10  0.9708277

我想用0替换整个df中的所有NA。我读了this blog post，然后尝试：

mydf |> replace(is.na(_), '') # Error in replace(mydf, is.na("_"), "") : invalid use of pipe placeholder
mydf |> mutate(across(everything(), .fns = ~replace_na(_, 0))) # Error in mydf |> mutate(across(everything(), .fns = ~replace_na("_", 0))) : invalid use of pipe placeholder

mydf |> mutate(across(everything(), .fns = ~replace_na(data = _, 0))) # same error, tried passing placeholder to a named arg per the blog post "One thing that is different than the . placeholder is the fact that you need to pass the name of the argument that will receive the _ placeholder"

我如何用这种方式在我的dplyr链中将我的df中的所有NA替换为0？