您可以通过定义Promise.resolve()并在每次迭代中链接它来顺序地获取请求。

let urls = [];
Array(21).fill('').forEach((_,i)=>{
  urls.push('https://dummyjson.com/carts/'+(i+1));
});

let promise = Promise.resolve();
console.time('time execution');
urls.forEach((url,i) => {
  promise = promise.then(() => 
    fetch(url)
    .then(r => r.json())
    .then(r => console.log(r))
    .catch(e => console.error(e))
    .finally(() => {
      if(i === urls.length - 1) console.timeEnd('time execution');
    }) 
  );
});

另一种方式：使用异步等待

let urls = [];
Array(21).fill('').forEach((_,i)=>{
  urls.push('https://dummyjson.com/carts/'+(i+1));
});

(async () => {
  console.time('time execution')
  for(let [i,url] of urls.entries()) {
    console.log(await new Promise((resolve, reject) => {
      fetch(url)
      .then(r => r.json())
      .then(r => resolve(r))
      .catch(e => reject(e))
      .finally(() => {
        if(i === urls.length - 1) console.timeEnd('time execution');
      });
    }));
  }
})();

您可以使用类似p-limit的工具手动执行此操作
示例：

import pLimit from 'p-limit';

const limit = pLimit(1);

async function getData(x: number) {
  // do whatever you neeed aasynchronously here
  return x;
}

async function otherFunction() {
  // some input parameters for the async getData function:
  const input = [1, 2, 3, 4, 5, 6, 7, 8, 9, 10];

  // set concurrency limit to 5:
  const limit = pLimit(5);

  // run Promite.all on the closures processed by your `limit`
  return Promise.all(input.map(e => limit(() => getData(e))));
}