选项1：创建联合类型

export type Status1 = typeof StatusTypes[number] & {
    desc: string;
    count: number | null
}

选项2：生成泛型类型

export interface Status2<Id extends typeof StatusTypes[number]['id']> {
    id: Id,
    name: Extract<typeof StatusTypes[number], { id: Id }>['name'],
    desc: string;
    count: number | null
}

旁注：
将类型保存为Map而不是数组可能更简洁

type StatusTypes = {
    1: { id: 1, name: 'Failed', },
    2: { id: 2, name: 'Awaiting', },
    3: { id: 3, name: 'Running', },
    4: { id: 4, name: 'Processed', },
}

根据您的环境和类型源考虑这一点