我不知道如何才能轻松解决这个问题，但有一个变通办法。您可以创建自定义id生成器类。别忘了，在设置ID之前，你必须检查数据库中ID的最后一个值。
以下是示例：

@Service
public class CustomIdGenerator {

    private static final String PREFIX = "R";
    private static AtomicInteger counter;

    private final YourRepository yourRepository;

    public CustomIdGenerator(YourRepository yourRepository) {
        this.yourRepository = yourRepository;
    }

    @PostConstruct
    private void init() {
        int lastId = getLastIdFromDatabase();
        counter = new AtomicInteger(lastId);
    }

    public String generateId() {
        return PREFIX + counter.incrementAndGet();
    }

    private int getLastIdFromDatabase() {
        String lastId = yourRepository.findLastId();
        if (lastId == null) {
            return 2023000;
        }
        return Integer.parseInt(lastId.substring(PREFIX.length()));
    }
}

    @Repository
    public interface YourRepository extends JpaRepository<YourEntity,  String> {
        @Query(value = "SELECT id FROM your_table ORDER BY id
         DESC LIMIT 1", nativeQuery = true)
        String findLastId();
    }

使用方法：

public void saveYourEntity(YourEntity entity) {
        entity.setId(customIdGenerator.generateId());
        yourRepository.save(entity);
    }