WordPress自定义管理菜单下显示分类

lf5gs5x2  于 2023-04-29  发布在  WordPress
关注(0)|答案(3)|浏览(298)

我试图显示一个自定义分类下的管理菜单项,这只是一个网页i即http://example.com/wp-admin/admin.php?page=bla
根据WordPress Dev。页面show_in_menuregister_taxonomy它说:
'some string' -如果是现有的顶级页面,如'tools.php' or 'edit.php?post_type= page ',文章类型将被放置为该子菜单。
这是否意味着分类法不能在除这些之外的任何东西下显示?

PHP

<?php
// hook into the init action and call create_book_taxonomies when it fires
add_action( 'init', 'create_book_taxonomies', 0 );

// create two taxonomies, genres and writers for the post type "book"
function create_book_taxonomies() {
    // Add new taxonomy, make it hierarchical (like categories)
    $labels = array(
        'name'              => _x( 'Genres', 'taxonomy general name' ),
        'singular_name'     => _x( 'Genre', 'taxonomy singular name' ),
        'search_items'      => __( 'Search Genres' ),
        'all_items'         => __( 'All Genres' ),
        'parent_item'       => __( 'Parent Genre' ),
        'parent_item_colon' => __( 'Parent Genre:' ),
        'edit_item'         => __( 'Edit Genre' ),
        'update_item'       => __( 'Update Genre' ),
        'add_new_item'      => __( 'Add New Genre' ),
        'new_item_name'     => __( 'New Genre Name' ),
        'menu_name'         => __( 'Genre' ),
    );

    $args = array(
        'hierarchical'      => true,
        'labels'            => $labels,
        'show_ui'           => true,
        'show_in_menu'      => 'bla', // not working | tried admin.php?page=bla as well, also not working
        'show_admin_column' => true,
        'query_var'         => true,
        'rewrite'           => array( 'slug' => 'genre' ),
    );

    register_taxonomy( 'genre', array( 'book' ), $args );
}
2ekbmq32

2ekbmq321#

我已经找到了解决这个问题的方法,代码如下:

add_action( 'admin_menu', 'shmeh_menu' );
    add_action( 'parent_file', 'menu_highlight' );

    function shmeh_menu() {
        add_submenu_page( 'bla', 'Shmeh', 'Shmeh', 'manage_options', 'edit-tags.php?taxonomy=shmeh');
    }

    function menu_highlight( $parent_file ) {
        global $current_screen;

        $taxonomy = $current_screen->taxonomy;
        if ( $taxonomy == 'shmeh' ) {
            $parent_file = 'bla';
        }

        return $parent_file;
    }
bmvo0sr5

bmvo0sr52#

在您的分类注册中:

show_in_menu => true

然后,您需要添加子菜单页面:

$parent_slug = 'slug_for_parent_menu';
$page_title = 'Submenu Page Title';
$menu_title = 'Submenu Page Title';
$capability = 'manage_options';
$menu_slug = 'edit-tags.php?taxonomy=bla&post_type=custom_post_type_name';
$function = null;
$position = null;
add_submenu_page($parent_slug, $page_title, $menu_title, $capability, $menu_slug, $function, $position);

最后:

add_filter('parent_file', 'menu_highlight');    
function menu_highlight($parent_file) {
    global $plugin_page, $submenu_file, $post_type, $taxonomy;
    if ('custom_post_type_name' == $post_type) {
        if ($taxonomy == 'bla') {
            $plugin_page = 'edit-tags.php?taxonomy=bla&post_type= custom_post_type_name'; // the submenu slug 
            $submenu_file = 'edit-tags.php?taxonomy=bla&post_type= custom_post_type_name';    // the submenu slug
        }
    } 
    return $parent_file;
}

希望我把这些都写对了。在分类检查中嵌套任何其他if,并为其他post类型添加相同的。

luaexgnf

luaexgnf3#

假设我们的分类slug是vendor,我们想把它放在父菜单下的是my_menu
要授予访问权限,将使用默认的manage_categoriescapability。这需要与在$args参数中传递的capabilities数组中提供给register_taxonomy函数的值匹配。

add_action('admin_menu', function (): void {
    add_submenu_page(
        'my_menu',              // parent_slug
        'Vendors',              // page_title
        'Vendors',              // menu_title
        'manage_categories',    // capability
        'edit-tags.php?taxonomy=vendor' // menu_slug
    );
});

add_action('parent_file', function (string $parent_file): string {
    global $current_screen;

    if ($current_screen->taxonomy === 'vendors') {
        return 'my_menu';
    }

    return $parent_file;
});

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