多值插入语法为：

insert into table values (1,1), (1,2), (1,3), (2,1);

但是krokodilko的回答要圆滑得多。

尝试：

INSERT INTO user_subservices(user_id, subservice_id) 
SELECT 1 id, x
FROM    unnest(ARRAY[1,2,3,4,5,6,7,8,22,33]) x

演示：http：//www.sqlfiddle.com/#!15/9a006/1

krokodilko回答的简短版本：

insert into user_subservices(user_id, subservice_id) 
values(1, unnest(array[1, 2, 3]));

一个稍微相关的答案，因为每次我试图记住这个答案时，我都会发现这个问题。插入多行多列：

insert into user_subservices (user_id, subservice_id)
select *
from unnest(array[1, 2], array[3, 4]);

更健壮的示例，当您需要为另一个表中的每一行插入多行时：

INSERT INTO user_subservices (user_id, subservice_id)
SELECT users.id AS user_id, subservice_id
FROM users
CROSS JOIN unnest(ARRAY[1,2,3]) subservice_id;

导入值一次但避免重复的好方法如下：

insert into schema.mytable (col1,col2) 
select col1, col2 from schema.mytable 
UNION
values 
('row1-col1','row1-col2'),
('row2-col1','row2-col2'),
('row3-col1','row3-col2')
except
select col1, col2 from schema.mytable;

对于多个值，此函数可能会有所帮助。
此函数生成多个值

const _multiInsert = arrOfValues => {
    // removes lastCharacter
    const _remLastChar = str => str.slice(0, str.length - 1);

      let foramttedQuery = '';

      arrOfValues.forEach(row => {
        let newRow = '';
        for (const val of Object.values(row)) {
          let newValue = '';
          if (typeof val === 'string') newValue = `'${val}',`;
          else newValue = `${val},`;
          newRow = newRow.concat(newValue);
        }

        foramttedQuery = foramttedQuery.concat(`(${_remLastChar(newRow)}),`);
      });

      return _remLastChar(foramttedQuery);
    };

    const arr_Of_Values = [
        {
            id: 1,
            name: "SAMPLE_NAME_1",
        },
        {
            id: 2,
            name: "SAMPLE_NAME2",
        }
    ]

    const query_template = `INSERT INTO TABLE_NAME VALUES ${_multiInsert(arr_Of_Values)}`
    
 console.log(query_template)