javascript 循环遍历JSON对象以获取特定键[duplicate]的值

cld4siwp 于 2023-05-05 发布在 Java

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From an array of objects, extract value of a property as array（25个回答）
两年前关闭。

0: {id: "7B5B201E-35AA-48A1-B919-002445319F8B", name: "Naman Sabarwal"}

1: {id: "EA6672BA-4F7A-4214-A37F-00716CE698C9", name: "me name"}

2: {id: "01F29920-9206-42DF-8151-00A6A080C501", name: "Nitesh Negi"}

I want to get a list such that the list contains only the name key values.

listOfNames = ['sonu singh'，'me name'，'harman jain']

How to get all the values of the key 'name'?

JavaScript

来源：https://stackoverflow.com/questions/62444080/loop-through-json-object-to-get-values-of-particular-key

3条答案

按热度按时间

csga3l581#

listOfNames = jsonValues.map(x=>x.name)

赞(0）回复(0）举报 2023-05-05

wztqucjr2#

你可以尝试如下。

let data = [
        {id: "7B5B201E-35AA-48A1-B919-002445319F8B", name: "Naman Sabarwal"},
        {id: "EA6672BA-4F7A-4214-A37F-00716CE698C9", name: "me name"},
        {id: "01F29920-9206-42DF-8151-00A6A080C501", name: "Nitesh Negi"}
    ]; // assume the data is in array 

let result = data.map( d => d.name );

console.log(result);

赞(0）回复(0）举报 2023-05-05

tgabmvqs3#

如果是json对象，如details = [{id：“"，name：“"}，{id：“"，name：“"}，{id：“"，name：“"}]
你可以使用map函数

function getnames(){
  let names = []
  details.map((detail)=>{
    names.push({name:detail.name})
    return names
  })
}

要缩短此代码，请输入names =values.map（value=〉returnvalue.name）

赞(0）回复(0）举报 2023-05-05

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javascript 循环遍历JSON对象以获取特定键[duplicate]的值

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