您可以更改第一级模板的分隔符：

tmpl := template.New("name").Delims("<<",">>").Parse(...)

然后，将模板编写为：

I want to render <<.Foo>>.

but I don't want to render anything on this line, like {{.Bar}}...

{{define "outer"}}
I want to render {{.}}
{{end}}

{{$ignored := `but I don't want to render anything on this line, like {{.Bar}} or this template: [{{ .Status | toUpper }}{{ if eq .Status "firing" }}:{{ .Alerts.Firing | len }}{{ end }}] {{ .CommonLabels.alertname }} for {{ .CommonLabels.job }}`}}

{{template "outer" .Foo}}

{{$ignored}}

Render {{template "outer" .Foo}} again.

选项1：内部模板和外部模板使用不同的分隔符。

t := template.Must(template.New("").Delims("<<", ">>").Parse(`
I want to render <<.Foo>>.

but I don't want to render anything on this line, like {{.Bar}} or this template: [{{ .Status | toUpper }}{{ if eq .Status "firing" }}:{{ .Alerts.Firing | len }}{{ end }}] {{ .CommonLabels.alertname }} for {{ .CommonLabels.job }}

Render <<.Foo>> again.`))

本方案：

var buf bytes.Buffer
if err := t.Execute(&buf, map[string]any{"Foo": "foo"}); err != nil {
    log.Fatal(err)
}
fmt.Println(buf.String())

打印：

I want to render foo.

but I don't want to render anything on this line, like {{.Bar}} or this template: [{{ .Status | toUpper }}{{ if eq .Status "firing" }}:{{ .Alerts.Firing | len }}{{ end }}] {{ .CommonLabels.alertname }} for {{ .CommonLabels.job }}

Render foo again.

https://go.dev/play/p/ueqstNKVUWQ

**选项2：**将整行作为字符串文字输出。这要求行中的"被引用，但这并不像引用所有{{那么糟糕。

I want to render {{.Foo}}.

{{"but I don't want to render anything on this line, like {{.Bar}} or this template: [{{ .Status | toUpper }}{{ if eq .Status \"firing\" }}:{{ .Alerts.Firing | len }}{{ end }}] {{ .CommonLabels.alertname }} for {{ .CommonLabels.job }}"}}

Render {{.Foo}} again.

https://go.dev/play/p/ueqstNKVUWQ