由于我的Java知识不完整,我很难将此加密代码转换为Python代码。两者应该有完全相同的结果。如能提供帮助将不胜感激。
- Java函数 *
import javax.crypto.Cipher;
import javax.crypto.spec.SecretKeySpec;
import java.security.Key;
class Main
{
public static void main (String[] args) throws java.lang.Exception
{
String s = "testings";
Cipher cipher = Cipher.getInstance("Blowfish/ECB/PKCS5Padding");
Key key = new SecretKeySpec("6#26FRL$ZWD".getBytes(), "Blowfish");
cipher.init(1, key);
byte[] enc_bytes = cipher.doFinal(s.getBytes());
System.out.println(enc_bytes);
}
}
- Python等效 *
def PKCS5Padding(string):
byteNum = len(string)
packingLength = 8 - byteNum % 8
if packingLength == 8:
return string
else:
appendage = chr(packingLength) * packingLength
return string + appendage
def PandoraEncrypt(string):
from Crypto.Cipher import Blowfish
key = b'6#26FRL$ZWD'
c1 = Blowfish.new(key, Blowfish.MODE_ECB)
packedString = PKCS5Padding(string)
return c1.encrypt(packedString)
结果
Java函数:“??!”
Python函数:“4A-`*ã”
3条答案
按热度按时间i7uaboj41#
使用您的示例,我得到了Python和Java的相同输出。
Java:
Python:
在这两种情况下,输出都是
223950ff19fbea872fce0ee543692ba7
m3eecexj2#
使用chr代替str。
str * int -> repeated string
cedebl8k3#
https://stackoverflow.com/a/17139643/1645017回答正确python2.
对于python 3 https://pycryptodome.readthedocs.io/en/latest/index.html `
”