If I correctly understand, you need common ID 's for every condition.

If so, and if FOO, BAR are unique for per ID , then you can do this:

with the_table(ID, FOO, BAR) as(
select  1 , 100 , 200 union all
select   1 , 101 , 202 union all
select   1 , 102 , 205 union all
select   2 , 100 , 200 union all
select   2 , 101 , 222 union all
select   2 , 102 , 203 union all
select   3 , 100 , 201 union all
select   3 , 101 , 202 union all
select   3 , 102 , 204 union all
select   4 , 100 , 201 union all
select   4 , 101 , 202 union all
select   4 , 102 , 205
)

select id from the_table
where
(FOO = 100 and BAR = 201) or
(FOO = 101 AND BAR = 202) or
(FOO = 102 and BAR = 205)
group by id
having count(*) = 3

Note that here: count(*) = 3 , number 3 is count of conditions in where clause, for example if you have just one condition (FOO = 100 and BAR = 201) , then query is:

select id from the_table
where
(FOO = 100 and BAR = 201)
group by id
having count(*) = 1

No need for recursive CTE. FOR FOO = 100 and BAR = 200 and then FOO=101 and BAR = 202, you can do this.

with cte
as
(

SELECT ID,FOO,BAR
FROM TAB
WHERE FOO = 100 and BAR = 200
)
SELECT ID
FROM cte
WHERE FOO=101 and BAR = 202

For FOO = 100 and BAR = 201 and FOO = 101 AND BAR = 202 and FOO = 102 and BAR = 205, you can do this:

with cte
    as
    (

    SELECT ID,FOO,BAR
    FROM TAB
    WHERE FOO = 100 and BAR = 201
    )
    SELECT ID 
    FROM
    (SELECT ID,FOO,BAR
    FROM cte
    WHERE FOO=101 and BAR = 202
    ) result(ID,FOO,BAR)
    WHERE FOO=102 and BAR = 205