imap.list()列出所有文件夹和子文件夹，imap.list(directory = 'Inbox')列出Inbox的所有子文件夹。然后，您可以提取文件夹名称并搜索名称中包含/的所有文件夹，以找到子文件夹。

for folder in (imap.list()[1]):
    folder = folder.decode()                        # folder = '(\Marked \HasNoChildren) "/" "Inbox/Privare/Subfolder1"'
    flags, name = folder.split(' "/" ')             # name = 'Inbox/Private/Subfolder1'

    if '/' in name:
        split_val = name.split('/')
        folderName = split_val[-1]                  # folderName = 'Subfolder1'
        parents = split_val[0:-1]                   # parents = ['Inbox', 'Private']

    flags = flags.split('\\')
    flags.remove(flags[0])
    flags = [each.strip(' )') for each in flags]    # flags = ['Marked', 'HasChildren']

name = 'Inbox'    # Example of fetching list for directory
typ, data = imap.list(directory = name) 

# [ b'(\\Marked \\HasChildren) "/" "Inbox"',
#   b'(\\HasNoChildren) "/" "Inbox/Subfolder"' ]

希望这个能帮上忙

谢谢你们的帮助。我自己也想明白了。当你获取收件箱的状态时，你会得到一个dict，dict[1]是未读邮件的数量。如果它是空的，它只是返回“[b'']”，所以我写了一个if子句，它将我的输出与空收件箱no_mails = [b'']的输出进行比较，并告诉代码在所有子文件夹中运行这个。

from imap_tools import MailBox
with MailBox('imap.mail.com').login('test@mail.com', 'password') as mailbox:
    # get all folders
    for f in mailbox.folder.list():
        print(f['name'])
    # get INBOX subfolders
    for f in mailbox.folder.list('INBOX'):
        print(f['name'])

https://github.com/ikvk/imap_tools

我遇到了这个答案，试图使它只会列出子文件夹内的收件箱，而不是所有文件夹。例如，如果文件夹设置为;

-INBOX
--folder1
---folder1-1
---folder1-2
--folder2

我只需要folder 1和folder 2，而不是folder 1 -1和folder 1 -2。做;

for folder in imap.list(pattern="/%")[1]:
    print(folder.decode().split(' "/" ')[1])

印刷品

INBOX/folder1
INBOX/folder2

从https://readthedocs.org/projects/imapclient/downloads/pdf/master/
“%匹配0个或多个字符，但文件夹分隔符”（“/"）除外。