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srand() — why call it only once?（7个回答）
4天前关闭。
我想在0和9之间快速创建新的随机数。为此修改了我在那里找到的代码：Why do I always get the same sequence of random numbers with rand()?并将其集成到循环中
我得到的输出是

Random fast seeded: 1
Random fast seeded: 1
Random fast seeded: 1
Random fast seeded: 1
Random fast seeded: 1
Random fast seeded: 1
Random fast seeded: 1
Random fast seeded: 1
Random fast seeded: 1
Random fast seeded: 1

相反，我想得到这样的东西：

Random fast seeded: 2
Random fast seeded: 8
Random fast seeded: 4
Random fast seeded: 7
Random fast seeded: 3
Random fast seeded: 1
Random fast seeded: 3
Random fast seeded: 5
Random fast seeded: 1
Random fast seeded: 9

下面是代码

#include <time.h>
#include <stdlib.h>
#include <stdio.h>

int main ()
{
  struct timespec ts;
  for (int i = 0; i<10; i++){
    clock_gettime(CLOCK_MONOTONIC, &ts);
    srand((unsigned int)ts.tv_nsec);
    printf ("Random fast seeded: %d\n", rand()%10);
  }
  return 0;
}

我做错了什么？