应单击accept the login及其后面的两个元素。只要等到元素变成可点击的，然后点击它。

WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Accept']"))).click()
#Your code
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.CSS_SELECTOR, "#loginForm > div > div:nth-child(3) > button"))).click()  
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Save Info']"))).click()
WebDriverWait(self.driver, 10).until(EC.element_to_be_clickable((By.XPATH, "//button[text()='Turn On']"))).click()

进口

from selenium.webdriver.common.by import By
from selenium.webdriver.support.ui import WebDriverWait 
from selenium.webdriver.support import expected_conditions as EC

试试这个：

self.driver.find_element_by_xpath("//button[text()='Accept']").click()

我在这里发布了我的解决方案：在www.example.com上使用Python/Selenium接受cookie错误www.instagram.com

你可以使用这个代码：

from selenium.webdriver.common.by import By
from selenium.webdriver.support.wait import WebDriverWait
from selenium.webdriver import Chrome
from selenium import webdriver
alert=WebDriverWait(driver, 15).until(EC.element_to_be_clickable((By.XPATH, '//button[contains(text(), "Accept All")]'))).click()

我找到了一种方法，通过选择相应文本的按钮。

from selenium import webdriver
from selenium.webdriver.common.by import By 
from selenium.webdriver.support.ui import WebDriverWait
from selenium.webdriver.support import expected_conditions as EC
cookie_button = WebDriverWait(wd,15).until(
                       EC.element_to_be_clickable(
                              (By.XPATH,
                               "//button[text()='Accept all cookies']")))
cookie_button.click()