javascript 排序数组对象[已关闭]

np8igboo 于 2023-06-04 发布在 Java

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作为一个绝对的javascript初学者，我目前正在一个todo应用程序上练习。应通过单击列标题，按标题、日期、状态和优先级对条目进行排序。附件是我的尝试，但我似乎做错了什么。有人能帮我吗？

const todos = [
  {id: 1, duedate: "2023-06-30", title: "Javascript Project 1", description: "first try", prio: 1, state: "done"}
];

const titleSort = document.getElementById("sort-title");

function sortTitle(a, b) {
  // alert("Titel sortieren");

  const titleA = a.title.toUpperCase();
  const titleB = b.title.toUpperCase();

  let comparison = 0;
  if (titleA > titleB) {
    comparison = 1;
  } else if (titleA < titleB) {
    comparison = -1;
  }
  return comparison;
}

titleSort.addEventListener("click", sortTitle);

JavaScript

来源：https://stackoverflow.com/questions/76397674/sort-array-objects

1条答案

按热度按时间

cl25kdpy1#

事件侦听器将把event对象传递给sortTitle函数…不是todos数组。你的回归将无处可去。
所以...对于事件侦听器，您必须传递一个要执行的函数。在该函数中，指定要排序的数组以及返回数组的位置。

const todos = [
  {id: 1, duedate: "2023-06-30", title: "Javascript Project 2", description: "second try", prio: 1, state: "done"},
  {id: 1, duedate: "2023-06-30", title: "Javascript Project 3", description: "third try", prio: 1, state: "done"},
  {id: 1, duedate: "2023-06-30", title: "Javascript Project 1", description: "first try", prio: 1, state: "done"}
];

const titleSort = document.getElementById("sort-title");

function sortTitle(array) {
  
  return array.sort((a,b) => {

    const titleA = a.title.toUpperCase();
    const titleB = b.title.toUpperCase();

    let comparison = 0;
    if (titleA > titleB) {
      comparison = 1;
    } else if (titleA < titleB) {
      comparison = -1;
    }
    return comparison;
  })
}

// I don't know where you want to return the sorted array... So I just console logged it.
titleSort.addEventListener("click", () => console.log(sortTitle(todos)));

.as-console-wrapper{
  max-height: 100% !important;
}

<button id='sort-title'>Sort me</button>

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javascript 排序数组对象[已关闭]

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