您可以循环遍历数组，然后为每个对象检查它是否具有createdDateTime属性。如果是，则使用新的Date对象更新$gte和$lte值。
你可以这样做：

// Assuming payloads is your initial array
const updatedPayloads = payloads.map(obj => {
  if(obj.hasOwnProperty('createdDateTime')) {
    let newObject = {...obj}; // clone the object to avoid modifying original
    if(newObject.createdDateTime.hasOwnProperty('$gte')) {
      newObject.createdDateTime['$gte'] = new Date(newObject.createdDateTime['$gte']);
    }
    if(newObject.createdDateTime.hasOwnProperty('$lte')) {
      newObject.createdDateTime['$lte'] = new Date(newObject.createdDateTime['$lte']);
    }
    return newObject;
  } else {
    return obj; // return object as it is if it does not contain 'createdDateTime'
  }
});

这段代码将创建一个名为updatedPayloads的新数组，其中日期字符串被Date对象替换。原始payloads阵列将保持不变。

有很多方法。一个是：

const firstObject = [
  {
    createdDateTime: {
      '$gte': '2023-02-08T00:00:00.000Z',
      '$lte': '2023-05-09T23:59:59.000Z'
    }
  },
  { user: 'customer' }
];

const secondObject = firstObject.map(obj => {
  if (obj.createdDateTime) {
    obj.createdDateTime['$gte'] = new Date(obj.createdDateTime['$gte']);
    obj.createdDateTime['$lte'] = new Date(obj.createdDateTime['$lte']);
  }

  return obj;
});

可以使用Array.forEach（）

filtersFromRequest.forEach( item =>{
    const createdDateTime = item.createDateTime;
    if( createdDateTime ){
        createdDateTime.$gte = new Date(createdDateTime.$gte);
        createdDateTime.$lte = new Date(createdDateTime.$lte);
    }
});