Sencha cmd，extJs 7：Fashion build退出，代码如下：2
我是ExtJS的新手，我试图使用 Sencha cmd在一个托管在mac os（m2芯片）上的**vagrant linux vm中创建一个项目。但我在执行sencha app watch时出错
我的步骤：
1.完全安装 Sencha cmd +所有扩展。./SenchaCmd-7.6.0.87-linux-amd64.sh -Dall=true -q
1.初始项目sencha app init --ext@7.6.0 --classic MyApp
1.编译开发sencha app watch
......
[INF] Writing content to /opt/bip/release/development/MyApp/build/development/MyApp/app.json
/root/bin/Sencha/Cmd/7.6.0.87/bin/linux-x64/node/node: 2: Syntax error: Unterminated quoted string
[ERR]
[ERR] BUILD FAILED
[ERR] com.sencha.exceptions.ExBuild: Fashion build exited with code : 2
.....
.....
[ERR] /root/bin/Sencha/Cmd/7.6.0.87/plugin.xml:378: The following error occurred while executing this line:
/root/bin/Sencha/Cmd/7.6.0.87/ant/build/app/build-impl.xml:253: The following error occurred while executing this line:
/root/bin/Sencha/Cmd/7.6.0.87/ant/build/app/watch-impl.xml:87: The following error occurred while executing this line:
/root/bin/Sencha/Cmd/7.6.0.87/ant/build/app/build-impl.xml:292: The following error occurred while executing this line:
/root/bin/Sencha/Cmd/7.6.0.87/ant/build/app/sass-impl.xml:205: The following error occurred while executing this line:
/root/bin/Sencha/Cmd/7.6.0.87/ant/build/app/sass-impl.xml:240: com.sencha.exceptions.ExBuild: Fashion build exited with code : 2我的环境：
Ubuntu 22.04.1 LTS
节点：v14.19.0
npm：6.14.16
java：openjdk版本“11.0.19”2023-04-18 LTS
ruby：ruby 3.0.2p107（2021-07-07修订版0 db 68 f0233）[aarch 64-linux-gnu]
我还尝试在本地机器上安装macOS版本，一切正常。错误仅出现在vm env中。非常感谢！
1条答案
按热度按时间xxls0lw81#
彦国！
你也可以运行 Sencha app build，这样它就可以向你显示关于错误的更多细节;
如果错误仍然存在，您可能必须在代码中进行双重检查，此错误。就像我看到的。您的App.json文件带有带引号的字符串错误。
上一篇：
Syntax error: Unterminated quoted string如果您打开该文件，它可能会在编辑器或IDE中显示错误。希望能帮上忙！