其中一种可能的方法是添加相关模型的post或pre-save信号，并根据此更新必要的字段。Django信号的官方文档，link。我想添加另一个link，我见过的关于Django信号的最好的博客文章之一。

编辑André Guerra响应

一个最简单的方法来做一个get调用，并带来批处理示例。我想说的是

@receiver(post_save,sender=Data)
def on_batch_child_saving(sender,instance,**kwargs):
    batch_instance = Batch.objects.get(pk=instance.batch)
    if (instance.timestamp < batch_instance.start): 
        batch_instance.start = instance.timestamp
        batch_instance.save()

    elif (instance.timestamp > batch_instance.end):
        batch_instance.end = instance.timestamp
        batch_instance.save()

根据Shakil的建议，我得出了这样的结论：（我在这里的疑问是如何保存父模型）

@receiver(post_save,sender=Data)
def on_batch_child_saving(sender,instance,**kwargs):
    if (instance.timestamp < instance.batch.start): 
        instance.batch.start = instance.timestamp
        instance.batch.save()

    elif (instance.timestamp > instance.batch.end):
        instance.batch.end = instance.timestamp
        instance.batch.save()

在Django中，你可以使用signal来更新父节点。为此，您需要创建一个信号来侦听子模型的post_save信号，并发送一个信号来更新父模型。

# models.py

from django.db import models
from django.dispatch import receiver
from django.db.models.signals import post_save

class Batch(models.Model):
    start = models.DateTimeField()
    end = models.DateTimeField()

class Data(models.Model):
    batch = models.ForeignKey(Batch, on_delete=models.ON_CASCADE)
    timestamp = models.DateTimeField()

@receiver(post_save,sender=Data)
def update_batch(sender,instance,**kwargs):
    batch = instance.batch
    if (instance.timestamp < batch.start): 
        batch.start = instance.timestamp

    elif (instance.timestamp > batch.end):
        batch.end = instance.timestamp

    batch.save()

有关更多信息，请参阅此answer。