我试图从FIR滤波器的WAV文件中获取数据。这就是我到目前为止所做的。这个代码是否正确阅读WAV？此外，我需要存储数据到一个双数组，以便能够将它们传递到FIR滤波器函数以后。我不知道该怎么做。
编辑：在阅读了一些有关WAV文件的更多信息后，我现在改变了我的代码。现在看起来好些了吗？如何将缺少数据的数组转换为双精度数组？

struct wav_header_t
{
    char chunkID[4]; //"RIFF" 
    unsigned long chunkSize; 
    char format[4]; //"WAVE" 
    char subchunk1ID[4]; //"fmt " 
    unsigned long subchunk1Size; //16 
    unsigned short audioFormat;
    unsigned short numChannels;
    unsigned long sampleRate;
    unsigned long byteRate;
    unsigned short blockAlign;
    unsigned short bitsPerSample;
};
//Chunks
struct chunk_t
{
    char ID[4]; //"data" 
    unsigned long size;  //Chunk data bytes
};
void WAV::vRead()
{
    //open file
    cout << sName <<" will be open"<<endl;
    FILE* handle;
    fopen_s(&handle, sName, "rb");
    if (handle == NULL)
    {
        cout << "file opened unsuccessfully" << endl;
        return;
    }
    else
    {
        cout << sName << " is open" << endl;
    }
    //size of file.wav
    fseek(handle, 0, SEEK_END);
    long fileSize = ftell(handle);
    //read wav-Headers
    wav_header_t header;
    fread(&header, sizeof(header), 1, handle);
    //Reading file
    chunk_t chunk;
    //go to data chunk
    while (true)
    {
        fread(&chunk, sizeof(chunk), 1, handle);
        if (*(unsigned int*)&chunk.ID == 0x61746164)
            break;
        //skip chunk data bytes
        fseek(handle, chunk.size, SEEK_CUR);
    }
    //Number of samples
    int sample_size = header.bitsPerSample / 8;
    int samples_count = chunk.size * 8 / header.bitsPerSample;
    short int* value = new short int[samples_count];
    memset(value, 0, sizeof(short int) * samples_count);
    //Reading data
    for (int i = 0; i < samples_count; i++)
    {
        fread(&value[i], sample_size, 1, handle);
    }
    fclose(handle);
    return;
}