在他的《C++ Move Semantics》一书中，Nicolai M. Josuttis指出，使用生成的移动构造函数移动包含可移动成员中的不可移动成员的对象，会移动除不可移动成员（被复制）之外的所有成员。下面是代码片段，它是书中示例的变体。

#include <iostream>
class Copyable {
    std::string name;
public:
    explicit Copyable(std::string name): name(std::move(name)) {}
    // Copying enabled
    Copyable(const Copyable& other): name(other.name) {
        std::cout << "Copyable copy ctor" << std::endl;
    }
    Copyable& operator=(const Copyable& other) {
        name=other.name;
        std::cout << "Copyable op=" << std::endl;
        return *this;
    }
    // Moving disabled with no copy fallback
    Copyable(Copyable&&) = delete;
    Copyable& operator=(Copyable&&) = delete;
};
class Movable {
    std::string name;
public:
    explicit Movable(std::string name): name(std::move(name)) {}
    // Copying enabled
    Movable(const Movable& other): name(other.name) {
        std::cout << "Movable copy ctor" << std::endl;
    }
    Movable& operator=(const Movable& other) {
        name=other.name;
        std::cout << "Movable op=" << std::endl;
        return *this;
    }
    // Moving enabled
    Movable(Movable&& other) noexcept: name(std::move(other.name)) {
        std::cout << "Movable move ctor" << std::endl;
    }
    Movable& operator=(Movable&& other) noexcept {
        name = std::move(other.name);
        std::cout << "Movable move op=" << std::endl;
        return *this;
    }
};
class Container {
    Copyable copyable;
    Movable movable;
public:
    Container(Copyable copyable, Movable movable): copyable(copyable), movable(std::move(movable)) {}
    // Both copying and moving enabled by default
};
int main() {
    Copyable c{"copyable"};
    Movable m{"movable"};
    Container container{c, m};
    Container container2{std::move(container)};
}

使用GCC在x86-64上编译，采用C++17标准，生成以下输出：
创建并初始化容器：

Copyable copy ctor
Movable copy ctor
Copyable copy ctor
Movable move ctor

移动容器：

Copyable copy ctor
Movable copy ctor

一旦容器移动，就不需要移动部件的移动执行器。根据书上的说法，movector应该被称为Movable member，对吗？