nuget用法为C++,如何复制源路径目录结构？

ldxq2e6h 于 2023-06-25 发布在其他

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我正在为C++构建nuget包。构建本身在服务器上使用jenkins执行。输出文件的布局如下：

D:/jenkins/workspace/myworkspace/build/Debug/package/lib/mylib.lib
D:/jenkins/workspace/myworkspace/build/Release/package/lib/mylib.lib
D:/jenkins/workspace/myworkspace/build/Release/package/include/subdir1/include1.h
D:/jenkins/workspace/myworkspace/build/Release/package/include/subdir2/include2.h

.nuspec看起来像这样：

<files>
 <file src="mylib.props" target="build\native\"/>
 <file src="build/Release/package/include/**/*" target="build\native"/>
 <file src="build/Release/package/lib/mylib.lib" target="build\native\lib\x64\Release"/>
 <file src="build/Debug/package/lib/mylib.lib" target="build\native\lib\x64\Debug"/>
</files>

打包完成后，在包内部，包含文件夹被打包，但布局为build/native/include/build/Release/package/include***。由于我使用复制目录结构，nuget也会复制上半部分。有没有办法更改基本目录，使路径变为build/native/include*

c++

来源：https://stackoverflow.com/questions/76188679/nuget-usage-for-c-how-do-i-copy-source-path-directory-structure

1条答案

按热度按时间

3qpi33ja1#

在nuget中有一个bug。未正确处理正斜杠（/）。所以下面的工作和预期的一样

<files>
 <file src="mylib.props" target="build\native\"/>
 <file src="build\Release\package\include\**\*" target="build\native"/>
 <file src="build\Release\package\lib\mylib.lib" target="build\native\lib\x64\Release"/>      
 <file src="build\Debug\package\lib\mylib.lib" target="build\native\lib\x64\Debug"/>     
</files>

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nuget用法为C++,如何复制源路径目录结构？

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