这是几天我一直在努力建立与iOS设备的BLE连接.一旦扫描成功找到我要查找的设备，就会调用以下代码，并且在android设备上运行良好。

void connect(Bike bike, BuildContext context) {
    String connectionId = ""; //foundDeviceId
    if (Platform.isIOS) {
      connectionId = bike.uuid; //On iOS the device ID is a UUID
    } else {
      connectionId = bike.mac; //On Android it is a MAC address
    }
    currentConnectionStream = bluetoothProvider.flutterReactiveBle
        .connectToDevice(
      id: connectionId,
      connectionTimeout: const Duration(seconds: 15),
    )
        .listen(
      (connectionState) {
        switch (connectionState.connectionState) {
          ...
        }
      },
      onError: (error) {
        cancelConnectionStream();
        log("ble_service error: " + (error as PlatformException).message!);
      },
    );
  }

当尝试连接到iOS设备时，我会收到以下错误日志提示，迫使.listen()函数立即跳转到OnError：

Unhandled Exception: PlatformException(invalidMethodCall(method: "disconnectFromDevice", details: Optional("\"deviceID\" is invalid")), invalid "disconnectFromDevice" method call ("deviceID" is invalid), null, null)

我已经尝试设置String connectionId与我的设备UUID的硬编码值，大写和小写，用破折号格式化...但仍然被错误消息卡住。
有人犯过这个错误吗？