我正在使用SwiftUI构建一个iOS应用程序，现在我正在尝试显示一个分为12个相等部分的圆周，所以它看起来像这样：
x1c 0d1x的数据
到目前为止，我通过使用12个圆来实现它，并将它们修剪到周长的1/12（添加0.001以在这些段之间留出一些空间）：

ZStack {
                Circle()
                    .trim(from:0.001, to: 1/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:1/12 + 0.001, to: 2/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:2/12 + 0.001, to: 3/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:3/12 + 0.001, to: 4/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:4/12 + 0.001, to: 5/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:5/12 + 0.001, to: 6/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
            }
            ZStack {
                Circle()
                    .trim(from:6/12 + 0.001, to: 7/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:7/12 + 0.001, to: 8/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:8/12 + 0.001, to: 9/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:9/12 + 0.001, to: 10/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:10/12 + 0.001, to: 11/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
                Circle()
                    .trim(from:11/12 + 0.001, to: 12/12 - 0.001)
                    .stroke(Color.black, lineWidth: 25)
            }
        }
        .padding(30)

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所以真实的的问题是 * 你会如何更优雅地实现这样的划分？***