You can use cross join for this. ie:

declare @start Date = '20230701';
declare @end Date = '20230731';

create table products (Product_ID int,  Product_Name varchar(20),   Unit_Price money);
insert into products (Product_ID,   Product_Name,   Unit_Price) values
(1,'Laptop',    400.00),
(2,'Keyboard',  20.00),
(3,'Monitor',150.00);

select d.theDate, p.Product_ID, p.Product_Name, p.Unit_Price
from products p
  cross join
(select top(datediff(d, @start, @end)+1) 
  dateadd(d, row_number() over (order by t1.object_id)-1, @start) as theDate
from sys.all_columns t1 
cross join sys.all_columns t2) d;

fiddle

EDIT: Explanation on how it works. You pass start and end dates as variables. Using sys.all_columns (because it has enough rows for our purposes out of the box) we generate dates from start to end date. row_number() over (order by t1.object_id) -object_id is an arbitrary selected column- we get a sequence like 1,2,3....N and limit the rows using TOP( datediff(d, @start, @end)+1). For 2023\07\01 to 2023\07\02 it would be 2 as an example (TOP(2)). Then we use the value from row_number() which is 1,2, ..., N in dateadd(d, row_number() over (...)-1 ,@start) thus generating dates from @start to @end inclusive.

Last we cross join that 'dates' returned from subquery with the products to get the result.

Here's another simple way to generate a list of numbers you can use for a series of dates and it should be very performant - this example will return from today + 30 days:

declare @start Date = GetDate(), @end Date = DateAdd(day, 30, GetDate());

with
  t1(n) as (select n from(values(0),(0),(0),(0),(0),(0),(0),(0),(0),(0))n(n)), 
  t2(n) as (select 1 from t1 x cross join t1 y), /* up to 100 rows - expand if more range required */
  t(n) as (select top (DateDiff(day, @start, @end)) Row_Number() over (order by (select null)) - 1 from t2)

select DateAdd(day, n, @start) [Date], p.*
from products p
cross join t
order by [date];

Demo Fiddle