SQL Server SQL: Aggregate DISTINCT vs. GROUP BY Columns

kqqjbcuj 于 2023-08-02 发布在其他

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Apologies if there is a duplicate question. I couldn't find one.

This is in SQL Server (Azure Synapse)

I have a table with 150+ columns and I am trying to get an aggregate COUNT( DISTINCT ) over a few of them.

Here is (a subset of) my query:

SELECT *
    ,count(DISTINCT XXX) AS Invoice_Count
    ,count(DISTINCT YYY) AS PO_Count
    ,count(DISTINCT ZZZ) AS PO_Item_Count
    ,'INV_WT_PO' AS Source_Identifier
    ,concat(XXX, YYY) AS Reference_Key
FROM [XXX].[YYY]

But I am getting the usual error:

XXX is invalid in the select list because it is not contained in either an aggregate function or the GROUP BY clause.

I understand the obvious solution would be to mention all the 150+ columns in the GROUP BY clause.

I did that and it worked but the performance is ABYSMAL. 1 minute 40 seconds vs. under 1 second for the query without the aggregate columns and GROUP BY clause.

I am curious if there is a better way to address this?

Thanks.

sql-server

来源：https://stackoverflow.com/questions/76616782/sql-aggregate-distinct-vs-group-by-columns

1条答案

按热度按时间

m1m5dgzv1#

I replicated the issue in my environment with sample data.

I have run the given code according to my data I got the same error.

I tried with below code without using group by clause.

SELECT *,
       (SELECT COUNT(DISTINCT XXX) FROM [XXX].[YYY]) AS Invoice_Count,
       (SELECT COUNT(DISTINCT YYY) FROM [XXX].[YYY]) AS Age_Count,
       (SELECT COUNT(DISTINCT ZZZ) FROM [XXX].[YYY]) AS Name_Count,
       'INV_WT_PO' AS Source_Identifier,
       CONCAT(XXX, YYY) AS Reference_Key
FROM [XXX].[YYY]

Output:

If you are having more than 150 columns as @Squirrel said you can try with COUNT(DISTINCT ) OVER( ) .

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SQL Server SQL: Aggregate DISTINCT vs. GROUP BY Columns

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