可以使用sed：

sed 's/^\s*//g;s/^[0-9]*/"&",/g;s/, "/,"/g' temp_data_count.txt

字符串
这将给予你的结果：

"1","Brian","192-11-0292","operations"
"1","John","001-01-0001","engineering"
"1","Lucius","992-11-0292","human resources"
"2","Smith","192-11-0292","human resources"

型
它按顺序使用三个替换：

1. s/^\s*//g将删除前导空格（从uniq -c输出）
2. s/^[0-9]*/"&",/g将抓取第一个数字，并将其与引号和逗号放在一起
3. s/, "/,"/g删除数字后面的空格

纯awk溶液：

awk '{ a[$0]++ } END { for (i in a) print "\"" a[i] "\"," i; }' temp_data.txt

字符串
印刷品

"2","Smith","192-11-0292","human resources"
"1","Lucius","992-11-0292","human resources"
"1","Brian","192-11-0292","operations"
"1","John","001-01-0001","engineering"

型
前提是我修复了从问题复制的数据中的不同尾随空格。（顺序不详。）
此解决方案使用整个输入行作为关联数组的键，并递增该值以计算相同行的数量。最后，数组键（=输入行）和值（=计数器）以指定的格式在循环中被指定。
使用GNU awk，您可以通过设置PROCINFO["sorted_in"]来获得排序输出。
比如说

awk '{ a[$0]++ } END { PROCINFO["sorted_in"]="@ind_str_asc"; for (i in a) print "\"" a[i] "\"," i; }' temp_data.txt

型
结果是按字符串的值以升序进行排序。

"1","Brian","192-11-0292","operations"
"1","John","001-01-0001","engineering"
"1","Lucius","992-11-0292","human resources"
"2","Smith","192-11-0292","human resources"

型
参见https://www.gnu.org/software/gawk/manual/html_node/Controlling-Scanning.html
或另一个sed后处理

sort temp_data.txt|uniq -c|sed 's/^\s*\([0-9]*\)\s*/"\1",/'

型
在行的开头替换任意数量的空格，后跟任意数量的数字（捕获为组1），后跟任意数量的空格，捕获的数字用引号和逗号括起来。

你们关系很好第一个月
抱歉，完全错了。
@Bodo展示了如何正确地执行此操作，以及无序和排序的输出。为了保持原始顺序，我们需要在第一次看到每条记录时跟踪行号。特别使用GNU awk

gawk '
  !lineno[$0] {lineno[$0] = NR}
  {count[$0]++}
  END {
    PROCINFO["sorted_in"] = "@val_num_asc"
    for (line in lineno)
      printf "\"%d\",%s\n", count[line], line
  }
' temp_data.txt

个字符
对于任何awk，这将产生相同的输出，对文件循环两次

awk '
  NR == FNR {count[$0]++; next}
  !seen[$0]++ {printf "\"%d\",%s\n", count[$0], $0}
' temp_data.txt temp_data.txt

型