您提供的SQL查询看起来几乎是准确的，但是有几个问题。GROUP BY子句是不必要的，您必须分别考虑每个部门内的级别（rn）。您可以通过在ROW_NUMBER()函数中使用PARTITION BY子句沿着ORDER BY子句来实现这一点。下面是更正后的SQL查询：

SELECT *
FROM (
    SELECT
        emp_id,
        dept_id,
        salary,
        ROW_NUMBER() OVER (PARTITIONED BY dept_id ORDER BY salary DESC) AS rn
    FROM
        employee
) ranked_employee
WHERE rn = 3;

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在这个查询中，ROW_NUMBER()函数根据薪水的降序为每个部门中的每一行生成一个唯一的等级。PARTITIONED BY dept_id可确保为每个部门单独进行排名。然后，在外部查询中，我们选择rank（rn）等于3的行，这对应于每个部门中工资最高的第三个员工。

使用分析RANK或DENSE_RANK函数，具体取决于您要如何处理关系。

CREATE TABLE departments(  department_id, department_name) AS
SELECT 1, 'IT' FROM DUAL UNION ALL
SELECT 2, 'Sales' FROM DUAL UNION ALL
SELECT 3, 'Marketing' FROM DUAL UNION ALL
SELECT 4, 'Finance' FROM DUAL;

CREATE TABLE employees (employee_id, first_name, last_name, hire_date, salary,  department_id) AS
SELECT 1, 'Lisa', 'Saladino', DATE '2001-04-03', 160000, 1 FROM DUAL UNION ALL
SELECT 2, 'Sandy', 'Herring', DATE '2011-08-04', 150200, 1 FROM DUAL UNION ALL
SELECT 3, 'Beth', 'Cooper', DATE '2019-03-05', 60700, 1 FROM DUAL UNION ALL
SELECT 4, 'Carol', 'Orr', DATE '2007-11-11', 70125,1 FROM DUAL UNION ALL
SELECT 5, 'Vicky', 'Palazzo', DATE '2004-09-17', 68525,2 FROM DUAL UNION ALL
SELECT 6, 'Cheryl', 'Ford', DATE '2020-05-10', 110000,1 FROM DUAL UNION ALL
SELECT 7, 'Leslee', 'Altman', DATE '2008-12-10', 66666, 1 FROM DUAL UNION ALL
SELECT 8, 'Jill', 'Coralnick', DATE '2001-04-11', 190000, 2 FROM DUAL UNION ALL
SELECT 9, 'Faith', 'Aaron', DATE '2001-04-17', 122000,2 FROM DUAL UNION ALL
SELECT 10, 'Silvio', 'Dante', DATE '2022-10-16', 102150,4 FROM DUAL UNION ALL
SELECT 11, 'Jerry', 'Torchiano', DATE '2022-10-30', 112660,4 FROM DUAL;

select  rnk, last_name, department_id, salary 
from    (
    select  last_name, department_id, salary,
        RANK () OVER ( PARTITION BY  department_id
                   ORDER BY      salary DESC
                 ) AS rnk
    from    employees
    )
where   rnk = 3

RNK LAST_NAME DEPARTMENT_ID SALARY
3 Ford 1 110000
3 Palazzo 2 68525

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