从std::addressof在https://en.cppreference.com/w/cpp/memory/addressof上的可能实现来看，它指出“std：：addressof的正确实现需要编译器支持”。为什么会这样呢？
我在https://godbolt.org/z/vnzbs9aTG上试用了这个实现，它像预期的那样工作。

#include <iostream>
#include <string>
#include <type_traits>

template<class T>
typename std::enable_if<std::is_object<T>::value, T*>::type addressof_impl(T& arg) noexcept
{
    return reinterpret_cast<T*>(
               &const_cast<char&>(
                   reinterpret_cast<const volatile char&>(arg)));
}
 
template<class T>
typename std::enable_if<!std::is_object<T>::value, T*>::type addressof_impl(T& arg) noexcept
{
    return &arg;
}

struct Student {
    std::string name{};
    int age{};
};

int main() {
    Student s;
    std::cout << addressof_impl(s);
    return EXIT_SUCCESS;
}

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