我在SAP中创建了一个Web服务,并尝试从Google应用程序脚本调用此SOAP Web服务。
这个WS是在BASIC身份验证中,在变量响应中,我接收到与我传入的输入相同的wsdl。
我在后端系统调用中遇到了问题
收到不支持的内容类型:”
有人能帮我吗
var user = 'user';
var pwd = 'pwd';
var webservice = 'http://xx.xxx.xx.xx:xxxx/sap/bc/srt/wsdl/flv_10002A111AD1/bndg_url/sap/bc/srt/rfc/sap/zdemo_google_ws/100/zdemo_google_ws/zdemo_google_ws?sap-client=100.wsdl';
function readData() {
//Clean up anything currently on the spreadsheet
SpreadsheetApp.getActiveSheet().clear();
try {
//Various XML parsing.
var xml = "<soapenv:Envelope xmlns:soapenv=\"http://schemas.xmlsoap.org/soap/envelope/\" xmlns:urn=\"urn:sap-com:document:sap:soap:functions:mc-style\">"
+"<soapenv:Header/>"
+" <soapenv:Body>"
+" <urn:ZDemoGoogle>"
+" <ItWebs>"
+" <item>"
+" <Protocol></Protocol>"
+" <Tasktype></Tasktype>"
+" <EntryId></EntryId>"
+" <Account></Account>"
+" <Mandt></Mandt>"
+" <Host></Host>"
+" <Port></Port>"
+" <Destination></Destination>"
+" <Path></Path>"
+" <Counter></Counter>"
+" <Calltime></Calltime>"
+" <ExecutionTi></ExecutionTi>"
+" <DataSend></DataSend>"
+" <DataSendTi></DataSendTi>"
+" <DataReceive></DataReceive>"
+" <DataReceiveTi></DataReceiveTi>"
+" </item>"
+" </ItWebs>"
+" </urn:ZDemoGoogle>"
+" </soapenv:Body>"
+"</soapenv:Envelope>"
var options = {
headers: {
"Authorization": "Basic " + Utilities.base64Encode(user + ':' + pwd),
"method" : "post",
"contentType" : "text/xml",
"payload" : xml,
"muteHttpExceptions":true
},
};
//UrlFetchApp is a powerful built-in library from Google
var serviceaddress = webservice ;
var response = UrlFetchApp.fetch(serviceaddress, options);
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1条答案
按热度按时间mfpqipee1#
要使用
UrlFetchApp.fetch()
,需要修改脚本的option
。那么这个修改怎么样?发件人:
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参考:
如果这不是你问题的直接解决方案,我很抱歉。