IEnumerable<string> e = (from char c in source
                        select new { Data = c.ToString() }).Select(t = > t.Data);
// or
IEnumerable<string> e = from char c in source
                        select c.ToString();
// or
IEnumerable<string> e = source.Select(c = > c.ToString());

然后你可以调用ToList()：

List<string> l = (from char c in source
                  select new { Data = c.ToString() }).Select(t = > t.Data).ToList();
// or
List<string> l = (from char c in source
                  select c.ToString()).ToList();
// or
List<string> l = source.Select(c = > c.ToString()).ToList();

如果你希望它是List<string>，去掉匿名类型，添加一个.ToList()调用：

List<string> list = (from char c in source
                     select c.ToString()).ToList();

尝试

var lst= (from char c in source select c.ToString()).ToList();

如果你有一个像"abcd"这样的字符串source，并想生成一个像这样的列表：

{ "a.a" },
{ "b.b" },
{ "c.c" },
{ "d.d" }

然后呼叫：

List<string> list = source.Select(c => String.Concat(c, ".", c)).ToList();

我想答案在下面

List<string> aa = (from char c in source
                    select c.ToString() ).ToList();

List<string> aa2 = (from char c1 in source
                    from char c2 in source
                    select string.Concat(c1, ".", c2)).ToList();