您可以使用for循环来迭代日期对象。对于每个步骤，将日期递增1。

const now = new Date();
const daysInFuture = 120;
const dates = getDatesInRange(now, daysInFuture);
const expectedEndDate = getFutureDate(now, daysInFuture - 1); // Exclusive

console.log(expectedEndDate.toString() === dates[dates.length - 1].toString());
console.log(dates.length === 120);
console.log(dates); // Show all the dates

function getDatesInRange(startDate, count) {
  const results = [], currDate = new Date(startDate.getTime());
  for (let i = 0; i < count; i++) {
    results.push(new Date(currDate.getTime()));
    currDate.setDate(currDate.getDate() + 1);
  }
  return results;
}

function getFutureDate(relativeDate, days) {
  const result = new Date(relativeDate.getTime());
  result.setDate(result.getDate() + days);
  return result;
}

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您可以使用getDate()获取当前日期，并增加天数，使用setDate()设置。你必须做120次才能达到极限。
要处理本地时间，

const currentDate = new Date();
const nextDates = [];
const dateLimit = 120;

for(let i = 1; i <= dateLimit; i++){
  const tempDate = new Date();
  tempDate.setDate(tempDate.getDate() + i);
  nextDates.push(tempDate);
}

console.log(nextDates)

对于UTC操作，使用

tempDate.setUTCDate(tempDate.getUTCDate() + i);

• 使用正则表达式解析将20230926转换为Date对象
• 创建一个数组并将其索引Map到从开始日期开始的天数
• 将日期格式化为所需的格式：

const input='20230926';
const length = 120;

const [, y, m, d] = input.match(/(\d{4})(\d{2})(\d{2})/);
const from = new Date(y, m - 1, d, 0, 0, 0, 0);
from.setMinutes(from.getMinutes() - from.getTimezoneOffset());

const pad = num => num.toString().padStart(2, '0');

const result = Array.from({length}, (_, i, dt = new Date(from)) => 
  dt.setDate(dt.getDate() + i) && 
    `${pad(dt.getDate())}-${pad(dt.getMonth() + 1)}-${dt.getFullYear()}`);

console.log(result);