php pdo未绑定值

vfh0ocws 于 2023-10-15 发布在 PHP

关注(0)|答案(3)|浏览(111)

我试图从mysqli迁移到pdo，但遇到了一个问题。

$sql = "select concat(register.fname ,' ' ,register.lname) as name,register.matric   as matric,register.username as uname,register.sex as sex,register.phone as phone ,register.passport as passport ,register.email as email,register.level as level,faculty.fac_name as fac,dept.dept_name as dept,diary.diary as diary,diary.date_added as added
        from register,faculty,dept,diary
        where register.user_id = :_id  and diary.username = :name limit 1";
$sth = $dbh->prepare($sql);
$sth->bindValue(':id', $id, PDO::PARAM_INT);
$sth->bindParam(':name', $username);
$sth->execute();

显示此错误：
警告：PDO语句：：bindValue（）[pdostatement.bindvalue]：SQLSTATE[HY093]：无效的参数号：会话信息：SESSION_ID = mjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjjj

php

来源：https://stackoverflow.com/questions/12826172/pdo-not-binding-value

3条答案

按热度按时间

jum4pzuy1#

在查询中，您在绑定值:id中将其命名为:_id。

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vjhs03f72#

您有:_id，请在bindValue调用中更改它

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tuwxkamq3#

你将变量$id绑定到:id，但在语句中你需要:_id。

$sth->bindValue(':_id', $id, PDO::PARAM_INT);

或者更改声明：

$sql = "select concat(register.fname ,' ' ,register.lname) as name,register.matric   as matric,register.username as uname,register.sex as sex,register.phone as phone ,register.passport as passport ,register.email as email,register.level as level,faculty.fac_name as fac,dept.dept_name as dept,diary.diary as diary,diary.date_added as added".
           "from register,faculty,dept,diary ".
          " where register.user_id = :id  and diary.username = :name limit 1";

赞(0）回复(0）举报 2023-10-15

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php pdo未绑定值

3条答案

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